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Minchanka [31]
2 years ago
5

In 10 seconds a car accelerates 4m/s^2 to 50

Physics
1 answer:
DanielleElmas [232]2 years ago
4 0

Answer:

10m/s

Explanation:

using the formula a=v-u

t

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A boy carries a 50 N box up a flight of stairs 10-m high. How much potential energy has the box gained?
almond37 [142]

Answer:

Potential energy, P = 500 J

Explanation:

We have,

Weight of the box, W = 50 N

Height of the stairs, h = 10 m

It is required to find the potential energy gained by the box. The potential energy is possessed by an object due to its height. The formula of potential energy is given by :

P=mgh

g is acceleration due to gravity

P=50\ N\times 10\ m\\\\P=500\ J

So, the potential energy of 500 J is gained by the box.

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3 years ago
What is the average translational KE of 5 moles of gas molecules at 300 K?
aev [14]

Answer:

What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Explanation:

The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

7 0
3 years ago
Which process allows a population Who become better adapted for survival in a specific environment
GalinKa [24]
Natural selection, it's simply when one animal outsmarts the rest and lives on to reproduce and carry on it's traits, when the animals who have not adapted well do not have the chance to reproduce, and the population dies off.
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3 years ago
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A ground-fault circuit interrupter is a (an) _____.
Arada [10]
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7 0
4 years ago
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A series RLC circuit consists of a 52.0 Ω resistor, a 4.80 mH inductor, and a 330 nF capacitor. It is connected to an oscillator
Tju [1.3M]

Answer:

(G) 75.11 ohm

(H) 0.08 A

(I) 46.2 degree

Explanation:

R = 52 ohm

L = 4.8 m H = 4.8 x 106-3 H

C = 330 nF = 330 x 10^-9 F

Vo = 6 V

(G)

f = 5000 Hz

Let the impedance is Z.

X_{L}= 2 \pi fL = 2 \times 3.14\times 5000\times 4.8\times 10^{-3}=150.72 ohm

X_{c}= \frac{1}{2 \pi fC}=\frac{1}{2\times 3.14\times 5000\times 330\times 10^{-9}}=96.51 ohm

Z=\sqrt{R^{2}+\left ( X_{L}-X_{c} \right )^{2}}

Z=\sqrt{52^{2}+\left (150.72-96.51)^{2}}=75.11 ohm

(H) Let Io be the peak current

I_{0}=\frac{V_{0}}{Z}=\frac{6}{75.11}=0.0798 A = 0.08 A

(I) Let Ф be the phase angle

tan\phi = \frac{X_{L}-X_{C}}{R}

tan\phi =\frac{150.72-96.51}}{52}=1.0425

Ф = 46.2 degree

4 0
3 years ago
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