In 10 seconds a car accelerates 4m/s^2 to 50

What is the weight of a 24.52kg Television dropped on pluto(acceleration of 0.59m/s/s)?

jolli1 [7]

W=ma=24.52*0.59 = ...

6 0

4 years ago

Read 2 more answers

22. State any three features of the electroscope.

MatroZZZ [7]

-1- was created in the 1600 by william gilbert
-2-When the charge is positive, electrons in the metal of the electroscope are attracted to the charge and move upward out of the leaves. This results in the leaves to have a temporary positive charge and because like charges repel, the leaves separate. When the charge is removed, the electrons return to their original positions and the leaves relax
3-

An electroscope is made up of a metal detector knob on top which is connected to a pair of metal leaves hanging from the bottom of the connecting rod. When no charge is present the metals leaves hang loosely downward. But, when an object with a charge is brought near an electroscope, one of the two things can happen.

7 0

3 years ago

If the capacity of the lungs of an adult were 3.8 L, how many moles of air would the lungs contain at body temperature and atmos

Ahat [919]

Answer:

0.14955 mol

Explanation:

We can solve this problem using the ideal gas law

$P \ V = \ n \ R \ T$

where P is the pressure, V the volume, n the number of moles, R the ideal gas constant and T the temperature.

We can use the atmospheric pressure as 1 atm, and the body temperature as 36.5 °C, in Kelvin this is:

$T_{body} = 36.5 \° C = (36.5 + 273.15) K = 309.65 \ K$

The ideal gas constant is:

$R = 0.082057 \frac{L \ atm}{ K \ mol}$

taking all this in consideration, the number of moles will be:

$n = \frac{P \ V}{ R \ T }$

$n = \frac{1 \ atm * 3.8 \ L }{ 0.082057 \frac{L \ atm}{ K \ mol}$ * 309.65 \ K } [/tex]

$n = 0.14955 \ mol$

3 0

3 years ago

you drop a 2 kg book to a friend who stand on the ground at distance D=10.0 m below, if your friends out streched hand at distan

MariettaO [177]

Work is defined as force*displacement so total d=8.5m and force will be 2kg*g which is roughly 20N of force so W = 20N*8.5m=170J

For part b the gravitational energy is m*g*h so gravitational energy = 200J since 2kg*10 m/s^2 *10m so the change since the work is 170 j means total change is 170J and 30J is left

8 0

4 years ago

Read 2 more answers

An insulating cup contains 200 grams of water at 25 ∘C. Some ice cubes at 0 ∘C is placed in the water. The system comes to equil

Nataly [62]

Answer:

The amount of ice added in gram is 32.77g

Explanation:

This problem bothers on the heat capacity of materials

Given data

Mass of water Mw= 200g

Temperature of water θw= 25°c

Temperature of ice θice= 0°c

Equilibrium Temperature θe= 12°c

Mass of ice Mi=???

The specific heat of ice Ci= 2090 J/(kg ∘C)

specific heat of water Cw = 4186 J/(kg ∘C)

latent heat of the ice to water transition Li= 3.33 x10^5 J/kg

heat heat loss by water = heat gained by ice

N/B let us understand something, heat gained by ice is in two phases

Heat require to melt ice at 0°C to water at 0°C

And the heat required to take water from 0°C to equilibrium temperature

Hence

MwCwΔθ=MiLi +MiCiΔθ

Substituting our data we have

200*4186*(25-12)=Mi*3.3x10^5+

Mi*2090(12-0)

837200*13=Mi*3.3x10^5+Mi*2090

10883600=332090Mi

Mi=10883600/332090

Mi= 32.77g

4 0

4 years ago