1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnom [1K]
3 years ago
8

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

-directed electric field of magnitude 670 N/CN/C ?
Physics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

q = 2.067 \times 10^{-5}\ C

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

q =\dfrac{mg}{E}

q =\dfrac{0.00141 \times 9.81}{670}

q = 2.067 \times 10^{-5}\ C

Charge of the particle is equal to q = 2.067 \times 10^{-5}\ C

You might be interested in
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
krek1111 [17]

Answer:

Explanation:

The path length difference = extra distance traveled

The destructive interference condition is:

\Delta d = (m+1/2)\lambda

where m =0,1, 2,3........

So, ←

\Delta d = (m+1/2)\lamb da9/tex]so [tex]\Delta d = \frac{\lambda}{2}

⇒ λ = 2Δd = 2×10 = 20

4 0
2 years ago
A circular loop of wire is in the plane of the paper. The south pole of a bar magnet is being moved from a position in front of
drek231 [11]

Answer:

Counterclockwise

explanation in attachment

5 0
3 years ago
Find the value of currents through each branch
Irina-Kira [14]

Answer:

the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

Explanation:

You can write the KVL equations:

Top left loop:

  I2(4) +(I2 +I3)(2) +I1(1) = 10

Bottom left loop:

  (I1-I2)(4) +(I1-I2-I3)(2) +I1(1) = 10

Right loop:

  (I2+I3)(2) +(I2+I3-I1)(2) = 5

In matrix form, the equations are ...

  \left[\begin{array}{ccc}1&6&2\\7&-6&-2\\-2&4&4\end{array}\right]\cdot\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}10\\10\\5\end{array}\right]

These equations have the solution ...

  \left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}2.500\\0.625\\1.875\end{array}\right]

This means the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

_____

This can be worked almost in your head by using the superposition theorem. When the 5V source is shorted, the 10V source is supplying (I1) to a circuit that is the 4 Ω and 2 Ω resistors in parallel with their counterparts, and that 2+1 Ω combination in series with 1 Ω for a total of a 4Ω load on the 10 V source. That is, I1 due to the 10V source is 2.5 A, and it is nominally split in half through the upper and lower branches of the circuit. There is no current flowing through the (shorted) 5 V source branch.

When the 10V source is shorted, the 5V source is supplying a 4 +4 Ω branch in parallel with a 2 +2 Ω branch, a total load of 8/3 Ω. This makes the current from that source (I3) be 5/(8/3) = 15/8 = 1.875 A. There is zero current from this source through the 1 Ω resistor.

Nominally, the current from the 5V source splits 2/3 through the 2 Ω branch and 1/3 through the 4 Ω branch.

Using superposition, I2 = I1/2 -I3/3 = (2.5 A/2) -(1/3)(15/8 A) = 0.625 A. This is the same answer as above, without any matrix math.

  (I1, I2, I3) = (2.5 A, 0.625 A, 1.875 A)

__

It helps to be familiar with the formulas for resistors in series and parallel.

8 0
2 years ago
where is the center of the universe located? and any 16 or older guys on here who are down to talk?? i got a pad we can talk on
bazaltina [42]

Answer:

the center of the universe is in your mom's stomach. why do I keep seeing people wanting to look for a date. the f. u. c. k.?

6 0
2 years ago
A person suffering from anaemia gets tired after a short walk​
FrozenT [24]

Answer:

yes

Explanation:

you will feel weary after shorter times

5 0
3 years ago
Read 2 more answers
Other questions:
  • An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0
    15·2 answers
  • In terms of substances explain why evaporation of water is a physical change and not a chemical change
    7·1 answer
  • A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at
    9·1 answer
  • A sinusoidal voltage is given by the expression ????(????)=20cos(5π×103 ????+60°) V. Determine its (a) frequency in hertz, (b) p
    5·1 answer
  • How do you make a electromagnet repel medal​
    14·1 answer
  • A woman throws a baseball straight up into the air. what is the baseball's acceleration at its highest point?
    10·1 answer
  • Gregory is visiting his grandmother, who lives 200 km from his house. While traveling there, Gregory had an average speed of 100
    9·2 answers
  • A car starts from rest and accelerates uniformly over a time of 10.21 seconds for a distance of 210 m. Determine the acceleratio
    10·1 answer
  • Lava from a volcano becomes solid as a result of
    8·2 answers
  • A baseball is given an initial velocity with magnitude v at the angle beta above the surface of an incline which in turn incline
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!