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Gnom [1K]
3 years ago
8

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

-directed electric field of magnitude 670 N/CN/C ?
Physics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

q = 2.067 \times 10^{-5}\ C

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

q =\dfrac{mg}{E}

q =\dfrac{0.00141 \times 9.81}{670}

q = 2.067 \times 10^{-5}\ C

Charge of the particle is equal to q = 2.067 \times 10^{-5}\ C

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3 years ago
A balloon drifts 140 m toward the west in 45 s; then the wind suddenly changes and the balloon flies 90 m toward the east in the
rusak2 [61]

Answer:

Explanation:

Given

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2 ) 90 m east in 25 s .

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f ) average in entire trip

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3 0
3 years ago
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podryga [215]

Answer: The given statement is false.

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7 0
3 years ago
Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 4.5 m long, its mass is 0.4
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density = 0.0933 kg/m

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