A motorboat accelerates uniformly from a velocity of 6.5m/s
to the west to a velocity of 1.5m/s to the west. if its accelerate was 2.7m/s2
to the east ,
how far did it travel during the accelration? Give your
answer in units of kilometers per hour/sec. To find the acceleration of the car
we have to
<span>
1. First determine
the suitable formula for this word problem.
Which is a. A=vf-vi/t</span>
which will be
Given are: Vi= 6.5 m/s Vf= 1.5 m/s a= 2.7 m/sec2 t=1.85s
Solution:
<span>
x = v0t + ½at2</span>
<span>x = <span>16.645375 m </span></span>
Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.
The distance between the resting point and maximum height of the wave is 0.2 cm.
The amplitude is measured from the resting point up to the highest point of the wave.
Answer:
p= 1.50289×10⁷ N/m²
Explanation:
Given
HA = (564 m)................(River Elevation)
HB = (2096 m).............(Village Elevation)
Area = A =(π/4){Diameter}² = (π/4){0.15 m}² = 0.017671 m²
ρ = (1 gram/cm³) = (1000 kg/m³)........(Water Density)
p(pressure)=?
Solution
p=PA - PB
p= ρ*g*HB - ρ*g*HA
p= (ρ*g)*(HB - HA)
p= (1000×9.81 )×{2096 - 564}
p= 1.50289×10⁷ N/m²
