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N76 [4]
3 years ago
12

The sum of three numbers is 74. The first number is three less than half the second number. if the third number is four times th

e second number what is the value of the first number?
Mathematics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

x=59/6

Step-by-step explanation:

Let's just say x+y+z=74

x=y-3

z=4y

So if we wanna convert everything into one variable, we get (y-3)+y+4y=74

Simplify and you get 6y=77

Now solve for y, and - 3 to get x

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Please helpp!
strojnjashka [21]

Answer:

2\frac{7}{9} \\

Step-by-step explanation:

-(2/9) + 3

= 27/9 - 2/9

= 25/9

= 2\frac{7}{9} \\

4 0
3 years ago
How do I turn 35 into a fraction?
timofeeve [1]
Every number is already a fraction, it just may not be written in the fraction form. 35 in the fraction written form is 35/1
8 0
3 years ago
I will give the brainiest answer
Amanda [17]

Answer:

6.2857142857 or 6.29 is the circumference of the circle

6 0
3 years ago
Read 2 more answers
Calculate y as a function of x when dy/dx = 4x3 + 3x2 - 6x + 5
PtichkaEL [24]
Answer:
y = x⁴ + x³ - 3x² + 5x + C

======

Separable differential equations such as these ones can be solved by treating dy/dx as a ratio of differentials. Then move the dx with all the x terms and move the dy with all the y terms. After that, integrate both sides of the equation.

   \begin{aligned}
\dfrac{dy}{dx} &= 4x^3 + 3x^2 - 6x + 5 \\
dy &= (4x^3 + 3x^2 - 6x + 5) dx \\
\int dy &= \int (4x^3 + 3x^2 - 6x + 5) dx 
\end{aligned}

In general (understood that +C portions are still there), 

   \int x^{m} = \dfrac{x^{m+1}}{m+1}

Note that ∫dy = y  since it is ∫1·dy = ∫y⁰ dy = y¹/(0+1) = y
For the right-hand side, we use the sum/difference rule for integrals, which says that

   \int \big[f(x) \pm g(x)\big]\, dx = \int f(x)\,dx \pm \int g(x) \, dx

Applying these concepts:

   \begin{aligned} 
 \int dy &= \int (4x^3 + 3x^2 - 6x + 5) \, dx \\
y &= \int 4x^3\,dx + \int 3x^2 \, dx - \int 6x\, dx + \int 5\, dx \\
&= \frac{4x^4}{4} + \frac{3x^3}{3} - \frac{6x^2}{2} + 5x + C \qquad \text{(only one $C$ is needed)} \\
&= x^4 + x^3 - 3x^2 + 5x + C
\end{aligned}

The answer is y = x⁴ + x³ - 3x² + 5x + C
6 0
3 years ago
Examination, 152 Candidates offered Agriculture
agasfer [191]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the given details

n(G)=136,n(P)=128,n(A)=152,n(A\cap G)=52,n(A\cap P)=60,n(A\cap P\cap G)=30,n(P\cap G)=58

STEP 2: Get the number of students that takes the subjects only

From the basic stuff, we have Number of candidates who had taken only each of the subjects

\begin{gathered} n(A\text{ only)=}n(A)-\lbrack n(A\cap P)+n(A\cap G)-n(A\cap P\cap G)_{}\rbrack \\ \Rightarrow152-\lbrack52+60-30\rbrack=152-82=70 \\  \\ n(G\text{ only)=}n(G)-\lbrack n(A\cap G)+n(P\cap G)-n(A\cap P\cap G)\rbrack \\ \Rightarrow136-\lbrack52+58-30\rbrack=56 \\  \\ n(P\text{ only)=}128-\lbrack58+60-30\rbrack=40 \end{gathered}

STEP 3: Represent the values above on a Venn Diagram after getting the values

STEP 4: Find the total number of candidate that sat for the exam.

\begin{gathered} We\text{ su}m\text{ all the numbers in the Venn diagram to get the total number of candidates that sat for the exam} \\ We\text{ have:} \\ 70+22+30+30+28+56+40=276 \end{gathered}

Hence, the total number of candidates that sat for the exam is 276

5 0
1 year ago
Read 2 more answers
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