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Misha Larkins [42]
3 years ago
14

Fancy Farms purchased equipment on January 1 at a cash cost of $30,000. The estimated life is 10 years and the estimated residua

l value is $5,000. Assuming the company uses the double-declining balance method of depreciation, the depreciation expense for the second year will be: ______.
Business
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

4,800

Explanation:

\left[\begin{array}{ccccc}Year&Beginning&Dep-Expense&Acc. \: Dep&Ending\\0&-&-&-&30,000\\1&30,000&6,000&6,000&24,000\\2&24,000&4,800&10,800&19,200\\3&19,200&3,840&14,640&15,360\\\end{array}\right]

The double declining will be the straight-line rate times two.

straight-line = 1/10

double declining = (1/10) x 2 = 2/10 = 1/5 = 20%

The first year will be:

30,000 x 20% = 6,000 depreciation expense

then we calculatethe book value for the second year

30,000 - 6,000 = 24,000

now we clacualte the depreciation expense for the 2nd year

24,000 x 20% = 4,800

This process is repeat every year until the book value equalt the salvage value at the end of the 10th year.

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The supply curve for oil shows:
12345 [234]
Supply of oil at different prices of other goods.
4 0
3 years ago
Depreciation--Jerry Company purchased machinery for $315,000 on May 1,2020 . It is estimated that it will have an useful life of
Gemiola [76]

Answer:

The depreciation for the first year is $75,000

Explanation:

In working hours method the depreciation on a fixed asset is charged using the ratio of numbers of hours utilized by the asset in a period and lifetime working capacity in hours.

First, we need to calculate the Depreciable value

Depreciable value = Cost of Asset - Salvage value = $315,000 - $15,000 = $300,000

Depreciation = Depreciable value x Numbers of hours worked / Total working capacity of Asset = $300,000 x 25,000 / 100,000 = $75,000

6 0
3 years ago
A father and mother are planning a savings program to put their daughter through college. Their daughter is now 8 years old. She
Anna71 [15]

Answer:

$4,102.57

Explanation:

we must first calculate the future costs of college:

cost of college year 1 = $16,200 x (1 + 2%)¹⁰ = $19,747.71

cost of college year 2 = $19,747.71 x 1.02 = $20,142.66

cost of college year 3 = $20,142.66 x 1.02 = $20,545.51

cost of college year 4 = $20,545.51 x 1.02 = $20,956.42

in order to determine how much money does the family need to have before college starts we must discount the cost of college by 7.5%:

PV cost of college year 1 = $19,747.71

PV cost of college year 2 = 20,142.66 / 1.075 = $18,737.36

PV cost of college year 3 = $20,545.51  / 1.075² = $17,778.70

PV cost of college year 4 = $20,956.42  / 1.075³ = $16,869.09

total = $73,132.86

the future value of the grandmother's deposits:

$13,000 x (1 + 7.5%)¹⁴ = $35,781.77

$2,900 x (1 + 7.5%)¹² = $6,907.16

total = $42,688.93

that means that you will need to save $73,132.86 - $42,688.93 = $30,443.93 by the time your child turns 18

you will make 4 deposits and their future value will be:

deposit x 1.075¹⁰ = 2.0610D

deposit x 1.075⁹ = 1.9172D

deposit x 1.075⁸ = 1.7835D

deposit x 1.075⁷ = 1.6590D

total = 7.4207D

yearly deposit = $30,443.93 / 7.4207 = $4,102.57

4 0
3 years ago
MJ LTD is expected to grow at various rates over the next five years. The company just paid a $1.00 dividend. The company expect
Black_prince [1.1K]

Answer:

$21.859

Explanation:

According to the scenario, computation of the given data are as follow:-

Present Value = D0 × (1 + growth rate)^time ÷ (1 + Required Rate of Return)^time period

1st Year PV = $1 × (1 + 0.20)^1 ÷ (1+ 0.12)^1

                  = 1.20 ÷ 1.12

                 = 1.071

2nd Year PV = $1 × (1 + 0.20)^2 ÷ (1+ 0.12)^2

                   = $1 × (1.44) ÷ 1.254

                  = $1.148

3rd Year PV = $1 × ( 1 + 0.20)^2 × (1 + 0.10) ÷ (1 + 0.12)^3

                    = $1 × (1.44) × (1.10) ÷ 1.405

                     = $1.127

4th Year PV = $1 × ( 1 + 0.20)^2 × (1 + 0.10)^2 ÷ ( 1 +0.12)^4

                    = $1 × (1.44) × (1.21) ÷ 1.574

                     = $1.107

5th Year PV = $1 × (1 + 0.20)^2 × ( 1 +0.10)^3 ÷ (1 + 0.12)^5

                     = $1 × (1.44) × (1.331) ÷ 1.762

                     = $1.088

6th Year PV = $1 × (1 + 0.20)^2 × (1 + .10)^3 × (1.05) ÷ [(0.12 - 0.05) × (1+.12)^5]

= $1 × (1.44) × (1.331) × (1.05) ÷ (0.07) ×  (1.762)

= $2.012 ÷ 0.1233

= $16.318

Now

Share’s Current Value is

= $1.071 + $1.148 + $1.127 + $1.107 + $1.088 + $16.318

= $21.859

We simply applied the above formula

5 0
3 years ago
You want to ctegsosit $15,00na bank at an interest rate of 7 percent per year What is the uture vale of this money after three y
Svetlanka [38]

Answer:

A $18, 375.63

Explanation:

The amount to be deposited is $15,000

Interest rate is 7 percent

time is 3 years

the future value will be; the applicable formula

A = p x ( 1 + r) ^n

A = $15,000 x ( 1 + 7/100) ^ 3

A= $15,000 x 1.225043

A=$18,375. 64

6 0
3 years ago
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