Question

Perimeter of a rectangle is 52 feet. If the length is 10 less than 2 times the width, what is the width?

Answer 1

Step-by-step explanation:

Let the width be x feet.

Therefore, length = 2x - 10

Perimeter of rectangle = 52

$2(2x - 10 + x) = 52 \\ 2(3x - 10) = 52 \\ \therefore \: 3x - 10 = \frac{52}{2} \\ \therefore \: 3x - 10 = 26\\ \therefore \: 3x = 26 + 10\\ \therefore \: 3x = 36 \\ \therefore \: x = \frac{36}{3} \\ \therefore \: x = 12 \\ \purple{ \boxed{\therefore \: width \: of \: rectangle = 12 \: feet }}$