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Oliga [24]
3 years ago
8

Perimeter of a rectangle is 52 feet. If the length is 10 less than 2 times the width, what is the width?

Mathematics
1 answer:
ella [17]3 years ago
6 0

Step-by-step explanation:

Let the width be x feet.

Therefore, length = 2x - 10

Perimeter of rectangle = 52

2(2x - 10 + x) = 52 \\ 2(3x - 10) = 52 \\ \therefore \:  3x - 10 =  \frac{52}{2} \\ \therefore \:  3x - 10 = 26\\ \therefore \:  3x = 26 + 10\\ \therefore \:  3x = 36 \\ \therefore \:  x =  \frac{36}{3} \\ \therefore \:  x =  12 \\ \purple{ \boxed{\therefore \: width \: of \: rectangle = 12 \: feet }}

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