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2 years ago

7

You have 125.0mL of a solution of H3PO4, but you don't know its concentration. If you titrate the solution with a 4.56M solution

of NaOH and reach the endpoint when 134.1mL of the base are added, what is the concentration of the acid?

1 answer:

Mariulka [41]2 years ago

5 0

4.89 mol/L

You can check the attached image for work.

-T.B.

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Diseases can spread rapidly in cities. If a disease kills many people in a city but fewer in a rural area, this is an example of

Inga [223]

Answer:

Density independent factor

Explanation:

in dense areas where people livein very close and tight spaces

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3 years ago

A piece of metal ore has a density of 1.72 g/mL. When a student places it into a graduated cylinder containing water, the liquid

Hunter-Best [27]

Answer:

9g

Explanation:

Since..., Density = mass/volume

;Firstly calculate the volume change of the water when the metal is placed in,

;Volume = 26.47 - 21.25

;Volume = 5.22 mL

Hence the mass of the ore;

; Making mass the subject of formula in the above equation,

Mass = Density × Volume

; Mass = 1.72 × 5.22

; Hence the mass = 8.9784

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3 years ago

The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).

garri49 [273]

Convert Mg to grams
1g =1000mg what about 3.91 Mg
= 3.91mg x 1g/1000mg= 3.91 x10^-3 g
moles= mass/molar mass
that is 3.91 x10^-3g /99 g/mol=3.95 x10^-5moles
concentration= moles / vol in liters

that is 3.95 x10^-5/100 x1000= 3.94 x10^-4M

equation for dissociation of CUCl= CUCl----> CU^+ +Cl^-

Ksp=(CU+)(CI-)
that is (3.95 x10^-4)(3.95 x10^-4)
Ksp= 1.56 x10^-7

3 0

3 years ago

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Find the maximum mass of MgO that can be made from 2.4 of Mg and 2.4 of O2

Yanka [14]

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3 years ago

125 ml of nitrogen gas is collected at 70.0 degrees Celsius. The pressure

dybincka [34]

Answer: Volume of the gas at STP is 22.53 L.

Explanation:

Given : Volume = 125 mL (as 1 mL = 0.001 L) = 0.125 L

Temperature = $70^{o}C = (70 + 273) K = 343 K$

Pressure = $125 kPa = 125 kPa \times \frac{0.01 atm}{1 kPa} = 1.25 atm$

According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$1.25 atm \times V = 1 mol \times 0.0821 L atm/mol K \times 343 K\\V = \frac{1 mol \times 0.0821 L atm/mol K \times 343 K}{1.25 atm}\\= \frac{28.1603}{1.25} L\\= 22.53 L$

Hence, volume of the gas at STP is 22.53 L.

5 0

2 years ago