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Pavel [41]
3 years ago
12

Given the following chemical equation, how many moles of carbon are necessary to react with 5.52 moles of SO2?5C(s) + 2SO2 (g) -

-> CS2 (l) + 4CO (g)
5.52 moles SO2
2.00 moles SO2
13.8 moles SO2
11.0 moles SO2
Chemistry
2 answers:
laila [671]3 years ago
7 0
The ratio between C and SO2 is 5:2 So....
take 5.52 * 5 / 2 = 13.8 mol C needed
sdas [7]3 years ago
3 0

Answer : The moles of carbon needed will be, 13.8 moles

Explanation : Given,

Moles of SO_2 = 5.52 mole

Now we have to calculate to moles of carbon.

The given balanced chemical reaction is,

5C(s)+2SO_2(g)\rightarrow CS_2(l)+4CO(g)

From the balanced chemical reaction, we conclude that

As, 2 mole of SO_2 react to give 5 moles of carbon

So, 5.52 mole of SO_2 react to give \frac{5}{2}\times 5.52=13.8 moles of carbon

Therefore, the moles of carbon needed will be, 13.8 moles

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Answer:

physical

Explanation:

no chemical reaction is happening

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The compound, nah2po4, is present in many baking powders. what is its name? sodium phosphate sodium bephosphate sodium dihydroge
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Explanation
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2.   ligand  are  named using alphabetical   order(for  our  case  h  for hydrogen come before p for  phosphate hence hydrogen is named first)

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8 0
3 years ago
If the pH of an acid is 4.0, what is the pOH?
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3 years ago
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If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
amid [387]

Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

                    1 mol                              2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

So

                  Na₂O              +   2 KCl    ----------->      2 NaCl          +      K₂O

             1 mol (62 g/mol)                                   2 mol (58.5 g/mol)

                  62 g                                                          117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

                           62 g of Na₂O ≅ 117 g of NaCl

                           25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

                          X g of NaCl = 117 g x 25 g / 62 g

                          X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

4 0
3 years ago
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