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Sergio039 [100]
3 years ago
15

these healthcare professionals are usually limited to the types of prescriptions they can write by a set standing orders.

Chemistry
1 answer:
Norma-Jean [14]3 years ago
5 0
I'm not sure what your question is?

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Imagine that small pieces of the metals copper, magnesium and iron are placed in three test tubes labeled A, B, and C, respectiv
Marizza181 [45]
A) Cu

Cu + 2HCl --> CuCl2 + H2(g)

Products predicted: Copper(II) choloride and hydrogen gas


B) Mg

Mg + 2HCl --> MgCl2 + H2

Products predicted: magnesium chloride + hygrogen gas

C) Fe

Fe +2 HCl -> FeCl2 + H2, or
2Fe +6 HCl -> 2FeCl3 + 3H2

Products predicted: Iron(II) chloride, iron (III) chloride and hydrogen gas.

8 0
3 years ago
What gas is used and what is released
Shalnov [3]

Answer:

if i got it right i think it woud be a

3 0
2 years ago
What is the entropy change of the surroundings
KiRa [710]

Answer: The entropy change of the surroundings will be -17.7 J/K mol.

Explanation: The enthalpy of vapourization for 1 mole of acetone is 31.3 kJ/mol

Amount of Acetone given = 10.8 g

Number of moles is calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of acetone = 58 g/mol

Number of moles = \frac{10.8}{58}=0.1862moles

If 1 mole of acetone has 32.3 kJ/mol of enthalpy, then

0.1862 moles will have = \frac{32.3}{1}\times 0.1862=5.828kJ/mol

To calculate the entropy change for the system, we use the formula:

\Delta S_{sys}=\frac{\Delta H_{vap}}{T(\text{ in K)}}

Temperature = 56.2°C = (273 + 56.2)K = 329.2K

Putting values in above equation, we get

\Delta S_{sys}=\frac{5.828}{329.2}=0.0177kJ/Kmol=17.7J/Kmol   (Conversion Factor: 1 kJ = 1000J)

At Boiling point, the liquid phase and gaseous phase of acetone are in equilibrium. Hence,

\Delta S_{system}+\Delta S_{surrounding}=0

\Delta S_{surrouding}=-\Delta S_{system}=-17.7J/Kmol

5 0
3 years ago
How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *
densk [106]

Answer:

26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

Explanation:

To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction),  and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?

molesofO_{2} =\frac{35 moles of FeCl_{3}*3 moles of O_{2}  }{4 moles of FeCl_{3}}

moles of O₂= 26.25 ≅ 26.3

<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>

7 0
3 years ago
The nuclear fission process releases neutrons and
yuradex [85]
<span>the answer is c. energy</span>
3 0
3 years ago
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