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Zanzabum
3 years ago
11

Hiroto’s texting plan costs $20 per month, plus $0.05 per text message that is sent or received. Emilia’s plan costs $10 per mon

th and $0.25 per text. Using the graph below, which statement is true?
Hiroto’s plan costs more than Emilia’s plan when more than 50 texts are sent.
Both plans cost the same when 22 texts are sent.
Emilia’s plan costs more than Hiroto’s plan when more than 22 texts are sent.
Both plans cost the same when 50 texts are sent.

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

both plans cost the same when 50 texts are sent. you answered correctly

Step-by-step explanation:


kifflom [539]3 years ago
5 0

Answer:

D

Step-by-step explanation:

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Simplify the following expression (w^8)8
Crank

Answer:

w^64

Step-by-step explanation:

(w^8)^8

both of the powers will be multiplied; hence

w^8*8

w^64

7 0
3 years ago
For the partially complete factorization, find the other binomial which will complete the factorization n^2-8n-20=(n+2)(_____)
Otrada [13]

Answer:

(n-10)

Step-by-step explanation:

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8 0
3 years ago
Lainey bought a set of 20 markers for $6 dollar sign, 6. What is the cost of 1 marker?
marin [14]
Hello!

To find the price of one marker you divide the price paid by the amount of markers bought

6 / 20 = 0.30

A marker cost $0.30

The answer is $0.30

Hope this helps!
5 0
3 years ago
Read 2 more answers
Help please its too hard
Varvara68 [4.7K]

Answer:

#6 = 1; #7 = A (5 gallons)

Step-by-step explanation:

#6 it is 1 because you are suppose to divide 10% of 50 which gave yuu $5 and then divide 5 by 20% which is 1

6 0
3 years ago
Determine the domain of the function h=9x/x(x^2-49)
Juliette [100K]

ANSWER

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

EXPLANATION

The given function is

h(x) =  \frac{9x}{x( {x}^{2} - 49) }

This function is defined for values where the denominator is not equal to zero.

x( {x}^{2}  - 49) \ne0

x(x - 7)(x + 7) = 0

The domain is

x \ne - 7, x \ne0, \: and \:  x \ne 7,

Or

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

8 0
3 years ago
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