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pav-90 [236]
3 years ago
15

Determine the equation for the given line in slope-intercept form. y = –x – 1 y = x + 1 y = x + 1 y = –x – 1

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

Answer is D on edge 2020

Step-by-step explanation:

just took the test got it right.

Evgesh-ka [11]3 years ago
5 0

Answer:

y = –x –

x – 1

Glad i could help!

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The area of a trapezoid field is 480 square m. The distance between two parallel sides is 15 m and one of the parallel sides is
Makovka662 [10]

Answer:

44m

Step-by-step explanation:

area  of a trapezoid = (a+b)* h/2

since the distance between two parallel sides is 15, that would be your height

plug everything in and you get:

480 = (20 + b) *15/2

b = 44

4 0
3 years ago
What is 9+-234*37^2-38/483
STatiana [176]
37292827 the answer is that
6 0
3 years ago
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What is the equation of the line that contains the point 46x30 and has a slope of -3?
BARSIC [14]

Answer:

y=-3x+30

Step-by-step explanation:

Written in: y=mx+b

6 0
3 years ago
Will vote
tia_tia [17]
The answer is 1 to 3
6 0
3 years ago
Convert the complex number z = 4 - 10i from rectangular form to polar form.​
mrs_skeptik [129]

ANSWER

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

EXPLANATION

The polar form of a complex number ,

z = x + yi

is given by:

z = r( \cos( \theta)  + i \sin( \theta) )

where

r =  \sqrt{ {x}^{2} +  {y}^{2}  }

The given complex number is:

z = 4 - 10i

r =  \sqrt{ {4}^{2}  +  {( - 10)}^{2} }

r =  \sqrt{16  + 100}

r =  \sqrt{116}  = 2 \sqrt{29}

And

\theta=  \tan^{ - 1}(\frac{ y}{x} )

\theta=  \tan^{ - 1}(\frac{  - 10}{4} )

\theta=  292 \degree

Hence the polar form is :

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

6 0
3 years ago
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