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Lady bird [3.3K]
3 years ago
7

What value is a discontinuity of x squared plus 5 x plus 2, all over x squared plus 2 x minus 35?

Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0
The value of discontinuity is x= -7, x= 5
Aleksandr-060686 [28]3 years ago
6 0

Answer:

x=-7 and x=5.  

Step-by-step explanation:

We have been given a rational function: f(x)=\frac{x^2+5x+2}{x^2+2x-35}. We are asked to find the points at which our function is discontinuous.

A rational function is discontinuous when the function is undefined or the denominator is zero.

Let us find what values of x will make our denominator zero.

x^2+2x-35=0

We will use factoring to find the zeros of x. By splitting the middle term we will get,

x^2+7x-5x-35=0

x(x+7)-5(x+7)=0

(x+7)(x-5)=0

(x+7)=0\text{ or }(x-5)=0

x=-7\text{ or }x=5

Therefore, at x equals -7 and x equals 5 our function is discontinuous.

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