Answer:
B) A series of chemical reactions where enzymes work one at a time to convert a reactant into intermediates and the intermediates into a final product.
Explanation:
In our cells there are multiple chemical reactions happening all the time to convert the elements we ingest (food, water, air) into the products the organism needs.
This processes can be very complex and offen involves various reactions (steps). Also, many of this reactions need to by catalized by enzymes in order to happen.
Answer:
See the explanation below, please.
Explanation:
In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.
In oxidation, electrons are lost (positive charge increases). Example:
Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)
On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:
Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)
Answer:
The answer would be this: an independent research organization test the product and record the results.
Answer:
you are a wich in wichcraft
Explanation:
Answer:
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Explanation:
From the given information:
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.
In this same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;
Rate factor in the absence of catalyst:

Rate factor in the presence of catalyst:

Assuming the catalyzed reaction and the uncatalyzed reaction are taking place at the same temperature :
Then;
the ratio of the rate factors can be expressed as:

![\dfrac{k_2}{k_1}={ \dfrac {e^{[ Ea_1 - Ea_2 ] }}{RT} }}](https://tex.z-dn.net/?f=%5Cdfrac%7Bk_2%7D%7Bk_1%7D%3D%7B%20%20%5Cdfrac%20%7Be%5E%7B%5B%20%20Ea_1%20-%20Ea_2%20%5D%20%7D%7D%7BRT%7D%20%7D%7D)
Thus;

Let say the assumed temperature = 25° C
= (25+ 273)K
= 298 K
Then ;



The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme