1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nataly862011 [7]
3 years ago
5

What is the name of the compound CO?

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0
Carbon monoxide (CO) is the name
Andru [333]3 years ago
3 0
<span>The answer is Carbon monoxide</span>
You might be interested in
How many moles of LiOH are needed to react completely with 25.5 g of CO2
LekaFEV [45]

Answer:

3.18 mol

Explanation:

2LiOH+CO_{2}-> Li_{2}CO_{3} +H_{2}O

n(CO2) = mass/ Mr.

             = 25.5 / 16

             = 1.59 mol

As per the equation above,

n(LiOH) : n(CO2)

     2      :    1

∴  3.18   :  1.59

     

3 0
2 years ago
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
What happens during a chemical reaction?
frozen [14]

Answer: The reactants’ bonds break, and bonds of the products form.

Explanation:

When a chemical reaction takes place, the bonds are broken and new bonds are formed to make new molecules. Like when 2 water molecules are broken down to form hydrogen and oxygen.

3 0
3 years ago
Read 2 more answers
A teardrop-shaped hill that points the direction a glacier has flowed is a:
mote1985 [20]
The answer is A Drumlin

3 0
3 years ago
Read 2 more answers
Other questions:
  • Choose the pure substance from the list below. Choose the pure substance from the list below.
    7·1 answer
  • What element has the same valence electrons as carbon A) N B) AI C) Si or D) Be
    9·1 answer
  • When the following reaction is completed and written in the form of a net ionic equation, which of the following elements will N
    13·1 answer
  • An aqueous 0.300 M glucose solution is prepared with a total volume of 0.150 L. The molecular weight of
    7·1 answer
  • A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
    12·1 answer
  • Formula for Tricarbon heptabromide.
    5·1 answer
  • Heyyy, please help, I only need the sentences for the words please. Thank uuu :)
    8·2 answers
  • How do i open the link when i get a question answered​
    6·1 answer
  • What is the Anion and it’s charge.
    8·1 answer
  • 4. The reaction of silver nitrate and potassium bromide yields silver bromide and potassium nitrate. If
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!