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3 years ago

What is the product of (–6.8)2? A. -13.6 B. 46.24 C. –46.24 D. 13.6

1 answer:

4 0

Note that -6.8 = -1*6.8. Therefore (-6.8)2 = (-1)*6.8*2. The product of 6.8*2 is 13.6. Hence (-6.8)2 = (-1)*13.6 = -13.6.

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Emma starts at one end of a 45-mile-long bike trail. After

aleksley [76]

Answer:

She has already reached the end of the trail.

Step-by-step explanation:

216 is a greater number than 45 miles

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2 years ago

In the equation y= -x/4, what is the unit rate?

maria [59]

The unit rate is -1/4.

8 0

2 years ago

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2 years ago

Read 2 more answers

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago

Y=x^2-2 Input output X Y 1 4 8 10

Nuetrik [128]

Answer: -1, 14, 62, 98

Step-by-step explanation:

Plug each x-value into the equation and solve for y

$\begin{array}{c|l||c}\underline{\quad x\quad}&\underline{x^2-2}&\underline{=\ y}\\1&1^2-2&=-1\\4&4^2-2&=14\\8&8^2-2&=62\\10&10^2-2&=98\end{array}$

7 0

2 years ago