The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
#SPJ1
Answer:
55 Rs.
Step-by-step explanation:
cost of the milk:
15.5 x 30 = 465 Rs.
Gross sales of the milk:
26 x 20 = 520 Rs.
Profit:
520 - 465 = 55 Rs.
Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved is a reflection across the _Y-axis _, followed by a reflection across the line _y=-x__.
ANSWER
EXPLANATION
The given line passes through;
(-1,-1) and it is parallel to x + y = 3.
This line given to us can be rewritten as
y=-x+1
It has slope m=-1.
The line parallel to this line also has slope m=-1.
We obtain the equation of the line using the formula:
We substitute the slope and the point to obtain:
The equation of the line is
