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patriot [66]
2 years ago
14

A right triangle has a side of length 1 fourth and a hypotenuse of length 1 third. What is the length of the other side?

Mathematics
1 answer:
Marina86 [1]2 years ago
5 0

Answer:

The other side = \frac{1}{12} units

Step-by-step explanation:

A right triangle has a side of length \frac{1}{4} units and;

the hypotenuse is \frac{1}{3}

According to Pythagorean theorem,

a² + b² = c² , where a and b are the two legs of a triangle and c is the hypotenuse.

Lets say a² = (\frac{1}{4}) ^2   and  c² = ((\frac{1}{3} )^2

b² = c² - a²

b² = \frac{1}{9} - \frac{1}{16} = \frac{1}{144}

So b = \sqrt{1/144} = \frac{1}{12} units.

So the other side = \frac{1}{12} units.

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No they are the same size because if you convert 1/4 into /16 it equals 5/16.
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5x + 3 = 7x – 1. Find x<br><br> a. 1/3<br> b. ½<br> c. 1<br> d. 2
weqwewe [10]

Answer:

Step-by-step explanation:

First you need to get like items on the same side(put the variables on one side and the non-variables on the other).  Remember anything you do on one side of the equal, you have to do on the other side, too.

5X+3=7X-1   I'm going to move the -1 first, but you don't have to as long as you keep the equation equal.

5X+3+1=7X-1+1    We know that +1-1 is zero and so is -1+1.  So

5X+3+1=7X      We don't need to keep that zero.

5X+4=7X         Now, we want to move the 5X over.

5X-5X+4=7X-5X    Simplify and get rid of the zero.

4=2X             Last, we have to divide to get the 2 away from the X.

4/2=2X/2            Not everyone know that slash mean divide, :-).

2=X

3 0
2 years ago
Find the length of the missing side.
Aleksandr [31]

Answer:

40

Step-by-step explanation:


5 0
2 years ago
State whether the following is reasonable or not. Explain your answer. Josefina gave away 130% of her stamp collection.
Nastasia [14]

Answer:

The statement is not reasonable.

Step-by-step explanation:

Josefina gave away 130% of her stamp collection.

We cannot give more than what we have.

lets understand it mathematically.

suppose i have x stamp.

according to question, i have to give 130% of my stamp collection

130% of x = 130/100 x = 1.3x

so, i have to given 1.3x stamp while i do have only x stamp which does not make any sense.

maximum i can give is x stamp.

x stamp in percentage of my total stamp collection which is also x will be

= x/x*100 = 100%

Thus, maximum one can give is 100% of what he has.

Thus, we can say that Josefina gave away 130% of her stamp collection is not reasonable.

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Yes it because any function can be a solution to any certain number of different systems
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