Question

The volumes of two similar solids are 8 ft3 and 125 ft3. The surface area of the smaller solid is 4 ft2. What is the surface area of the larger solid?

Answer 1

Answer:

25 square feet

Step-by-step explanation:

We are given that

Volume of smaller solid= 8 cubic feet

Volume of large solid=125 cubic feet

Surface area of smaller solid=4 square feet

We have to find the surface area of larger solid.

Volume of is a cubic function

Ratio of two solids=6:125

$\frac{V_1}{V_2}=\frac{2^3}{5^3}=\frac{a^3}{b^3}$

$\frac{a}{b}=\frac{2}{5}$

Where a= Side of small solid

b=Side of large solid

Ratio of corresponding sides of two solids=2:5

When two solids are similar then the ratio of surface area

$\frac{Area\;of\;small\;solids}{area\;of\;larger\;solids}=\frac{a^2}{b^2}$

Area of small solid: area of larger solid=$\frac{2^2}{5^2}$

4: area of large solid=4: 25

Area of larger solid=$\frac{4\times 25}{4}=25 ft^2$

Hence, the area of larger solid=25 square feet

Answer 2

Answer:

Surface area of larger solid is = 25 square feet.

Step-by-step explanation:

Given that,

Volume of smaller solid = 8 cubic feet

Volume of larger solid = 125 cubic feet

We know that,

Volume is the function of cube of dimensions.

and area is the function of square of dimensions.

So,

8 = 2³

125 = 5³

Ratio of sides = 2 : 5

Ratio of surface area = 4:x        (let surface area of larger solid x)

So,

$\frac{4}{x}=\frac{2^{2} }{5^{2} }$

x = 25 sq ft

surface area of the larger solid = 25 sq ft

That's the final answer.