Answer:
The weight of watermelon at the end of the trip is <u>500 kg.</u>
Step-by-step explanation:
Given:
The weight of watermelons is 1000kg.
At the beginning of the trip watermelon is 99% of the weight:
99% of 1000kg
![\frac{99}{100}\times 1000](https://tex.z-dn.net/?f=%5Cfrac%7B99%7D%7B100%7D%5Ctimes%201000)
![=0.99\times 1000](https://tex.z-dn.net/?f=%3D0.99%5Ctimes%201000)
kg
Now, at the end of the trip it is 98% of weight. So, let
kg of water has been evaporated. So, remaining weight of the watermelon is
.
If
kg of water is removed, then the amount of water left is
.
As per question, water now weighs 98% of the total weight. So,
98% of (
) = ![990-x](https://tex.z-dn.net/?f=990-x)
![\frac{98}{100}\times (1000-x)=990-x](https://tex.z-dn.net/?f=%5Cfrac%7B98%7D%7B100%7D%5Ctimes%20%281000-x%29%3D990-x)
![980-0.98x=990-x](https://tex.z-dn.net/?f=980-0.98x%3D990-x)
(Bringing like terms on one side)
![0.02x=10\\x=\frac{10}{0.02}=500\ kg](https://tex.z-dn.net/?f=0.02x%3D10%5C%5Cx%3D%5Cfrac%7B10%7D%7B0.02%7D%3D500%5C%20kg)
Therefore, the weight of watermelon at the end of the trip is given as:
Weight =
= 1000 - 500 = 500 kg
Therefore, the watermelon weighs 500 kg at the end of trip.