Answer:
<em>The metalworker should use 60 kg of metal alloy that is 70% copper and 40 kg of metal alloy that is 20% copper.</em>
Step-by-step explanation:
<u>System of Equations
</u>
Let's call
x=amount of metal alloy that is 20% copper
y=amount of metal alloy that is 70% copper
The metalworker wants to create 100 Kg of 50% copper alloy. This gives us the first relation
x+y=100
The combination of 20% of x and 70% of y will produce 50% of the sum of both, thus
20x+70y=50(x+y)
Operating
20x+70y=50x+50y
Reducing and dividing by 10
2y=3x
The system of equations is easily solved by isolating x in the first equation
x=100-y
And replacing into the last equation
2y=3(100-y)
Operating
2y=300-3y
5y=300
y=60
Thus
x=100-60=40
The metalworker should use 60 kg of metal alloy that is 70% copper and 40 kg of metal alloy that is 20% copper.
Ab is obtuse acute to AD
DC is perpendicular parallel to AB
9 divided by. 5 :)))))))))))))))))
Answer:
9
Step-by-step explanation:
(-9)^1/3 * (-81)^1/3
We can rewrite -81 as 9 * -9
So it can be rewritten as:
(-9)^1/3 * (9*-9)^1/3
Since they are all raised to the 1/3, we can combine the bases:
(-9*9*-9)^1/3 =
(9*9*9)^1/3, because the two negatives turn into a positive:
So this is basically:
(9^3)^1/3 = 9^1 = 9
Answer:
15y^5
Step-by-step explanation:
Formula for the area of a rectangle is length times width.
so in this case, it would be 15y^5!! Trust me I just did this!
