The string of a flying kite is being held five feet off the ground. It makes a 60 degree angle with one side parallel to the gro
und. If all 300 feet of string are out, and there is no sag in the string, how high is the kite above the ground? Billy says using cosine he got a height of 150' + 5' (off the ground) for a total of 155', but Maria argues that using special right triangles the height is approximately 260' + 5' for a total of 265'. Who is right and why?
1 answer:
Answer:
Maria is right
Height=265 ft
Step-by-step explanation:
In the attached diagram, the length of the kite is BC and the height of the Kite above the ground is CE.
Now, CE=CD+DE
DE=5 ft
Next, we have to determine the length of CD.
In Triangle BCD
Therefore:
CE=260+5=265 ft
From the above, we see that <u>Maria is right.</u>
Billy erroneously applied the wrong trigonometric ratio (Cosine) which made him get a value of 150ft.
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Answer:
The towel bar should be placed at a distance of from each edge of the door.
Step-by-step explanation:
Given:
Length of the towel bar =
Now given length is in mixed fraction we will convert in fraction.
To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.
can be Rewritten as
Length of the towel bar =
Length of the door =
can be Rewritten as
Length of the door =
We need to find the distance bar should be place at from each edge of the door.
Solution:
Let the distance of bar from each edge of the door be 'x'.
So as we placed the towel bar in the center of the door it divides into two i.e. '2x'
Now we can say that;
Now we will take LCM to make the denominators common we get;
Now denominators are common so we will solve the numerators.
Or
Hence The towel bar should be placed at a distance of from each edge of the door.