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3 years ago

The monthly sales (in thousands of units) of a seasonal product are approximated by

1 answer:

3 0

<span>Don't forget S is measured in thousands of units so you are solving for :

100 < 74.5 + 43.75Sin(πt/6)
25.5 < 43.75Sin(πt/6)
Sin(πt/6) >25.5/43.75 = 0.582857
ASrcSin(πt/6) > 0.62224 radians
πt/6 > 0.62224
t > 6 x 0.62224/π = 1.1884 (4dp)

This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3.
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116]

Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>

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Calculate the

notka56 [123]

Answer:

Portion of walking in degrees = 72°

Step-by-step explanation:

The question is incomplete as the diagram is not shown in the question. I have attached the full question below. Consult it to understand the solution better

First calculate the percentage of walking from a total of all activities.

Percentage of walking = 10/50 · 100%

Percentage of walking = 20%

It means the portion of the circle(pie chart) for walking should be equal to 20% of the whole circle.

We know that the whole circle is equals to 360°

Circle = 360°

We need to calculate 20% of 360°, which will represent the portion of walking in degrees.

Portion of walking in degrees = 20/100 · 360°

Portion of walking in degrees = 72°

7 0

3 years ago

AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

$m=\frac{5}{7}$

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

$\Rightarrow m_1\times m_2 =-1$

$\Rightarrow \frac{5}{7}\times m_2 =-1$

$\Rightarrow m_2 = \frac{-7}{5}$

So, Slope for line BC : $m_2 = \frac{-7}{5}$

Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

$7x+5y-48=0$

Hence the equation of line BC : $7x+5y-48=0$

5 0

3 years ago

Use the quadratic formula to solve the equation <br> 25x^2-30x+25=0

Reika [66]

Answer: $x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}$

Step-by-step explanation:

$25x^2-30x+25=0$

$x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}$

$\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}$

$=\sqrt{30^2-4\cdot \:25\cdot \:25}$

$=\sqrt{30^2-2500}$

$=i\sqrt{2500-30^2}$

$=40i$

$x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}$

$x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}$

$x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}$

8 0

3 years ago

Write an exponential function represented by the table

Alinara [238K]

Answer:

50y= -2248283

Step-by-step explanation:

used photo math

3 0

2 years ago

Which parent function is represented by the graph?

IRINA_888 [86]

I cant see all the choices but its a quadratic function#

4 0

3 years ago

Read 2 more answers