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scoundrel [369]
3 years ago
7

3. A jump rope is 9 feet long. How long is the jump 4 rope in yards?

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
The answer is 3 yards.

There are 3 feet in a yard, so if we divide 9 (the length of the rope in feet) by 3, then we get the amount of yards in the rope: 9/3=3.
Mars2501 [29]3 years ago
7 0
1 yard is 3 feet, 3+3+3=9 so the answer is 3 yards
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Mrs.Smith has two similiar recycling bins in her office. The dimension of the smaller bin can be found by dilating the dimension
nikklg [1K]

Answer:

The dimension of the larger bin is x and the smaller bin is 0.75x.

Step-by-step explanation:

Let the dimension of the larger bin is x.

It is given that the dimension of the smaller bin can be found by dilating the dimension of the larger bin by a scale factor of 0.75

In order to find the dimension of the smaller bin multiply the dimension of the larger bin by 0.75

(x)(0.75)=0.75x

Hence, the dimension of the larger bin is x and the smaller bin is 0.75x.

8 0
2 years ago
Evaluate each expression for w=5, x=3, y=4 and z=8.<br> 3y+6/2x
Aliun [14]
Plug in your numbers so the equation will turn out to be 3(4)+6/2(3) , you need to simplify 6/2 which will be 3 and 3 times 3 = 9 so the equation will be 3(4)+9 and 3 times 4 = 12 so the equation will now be 12+9 = 21
Answer= 21
4 0
3 years ago
#4 is tough for me can you help me and explain how you got the answers.
Gnoma [55]
You put the scores in order from least to greatest, then you have to find the middle number. Now you will end up with two middle numbers you add them and divide by 2 then u have it answer.
4 0
3 years ago
What is a statement that is assumed to be true without proof
aalyn [17]

Answer:

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4 0
3 years ago
Read 2 more answers
Use the following function to find the value of each operation.
Murljashka [212]
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>

w(f(m(2))) = 593

<h3>Step-by-step explanation:</h3>

We can write how w(f(m(x))) will be defined but that's too much work and it's only useful when we are evaluating w(f(m(x))) with many inputs.

First let's solve for m(2) first. As you read through this answer, you'll get the idea of what I'm doing.

Given:

m(x) = -4x +1

Solving for m(2):

m(2) = -4(2) +1 \\ m(2) = -8 +1 \\ m(2) = -7

Now we can solve for f(m(2)), since m(2) = -7, f(m(2)) = f(-7).

Given:

f(x)=3x-1

Solving for f(-7):

f(-7)=3(-7)-1 \\ f(-7) = -21 -1 \\ f(-7) = -22

Now we are can solve for w(-22). By now you should get the idea why w(f(m(2))) = w(-22).

Given:

w(x) = x^2 -5x -1

Solving for w(-22):

w(-22) = (-22)^2 -5(-22) -1 \\ w(-22) = 484 -5(-22) -1 \\ w(-22) = 484 +110 -1 \\ w(-22) = 593

8 0
3 years ago
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