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a_sh-v [17]
3 years ago
11

Please help question in the picture

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

We can think of this as a right triangle, where the given lengths are the legs.

So, we can solve using the Pythagorean Theorem.

21² + 28² = c²

441 + 784 = c²

1225 = c²

35 = c

35 miles

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Write an equation in slope-intercept form of the line shown.
7nadin3 [17]

Answer:

y = 2x - 5

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2

m = 2

Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in y = mx + b

-3 = (2)(1) + b

-3 = 2 + b

Subtract 2 from both sides

-3 - 2 = 2 + b - 2

-5 = b

b = -5

Plug in the value of m and b into the slope-intercept form equation, y = mx + b.

Thus:

y = 2x +(-5)

✅y = 2x - 5

5 0
3 years ago
I do not understand how I find answers on here
Volgvan
All you have to do is write your question and someone will answer. For example, instead of writing "I do not understand how I find answers on here" you would ask something like what is 9*5? Then 2 people will see your question and answer. There are no pre-recorded answers, everything happens live. Hope this helps!
6 0
3 years ago
I need help its the triangle sum theorem​
Dimas [21]
I think it might be C
4 0
3 years ago
I wasn’t so sure on how to solve this, anyone mind helping me?
sweet-ann [11.9K]

Answer:

Rays: A, B, C, D - 4 rays for each.

Line segments: AB, BD, DC, CA.

7 0
2 years ago
A gas station sells 1600 gallons of gasoline per hour if it charges $ 2.70 per gallon but only 900 gallons per hour if it charge
kakasveta [241]

Answer:

Look just at finding the linear model. Two points. Use price per gallon for x and gallons per hour sold for y. Your two points (x,y) are (2.15,1600) and (2.55,800).

Slope m=%281600-800%29%2F%280.15-0.55%29

m=800%2F0.40

m=2000

Using point-slope form for a line, and the lower-y point,

y-800=2000%28x-2.55%29

highlight%28y=2000%28x-2.55%29%2B800%29

5 0
2 years ago
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