The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:

<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:


Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:


Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Prime numbers from 1 to 50:
2, 3, 5, 7, 11, 13<span>, 17, 19, 23, 29, 31, </span>37,41<span>, </span>43<span>, </span><span>47</span>
Answer:
Translation +6 Left
and maybe a slight dilation that makes it bigger.
Hope this helps!