1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashutka [201]
3 years ago
5

What is the structure of carbon

Chemistry
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

Explanation:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

You might be interested in
The typical atmospheric pressure on top of Pikes Peak, Colorado (14109 ft. ) is 656.2 torr. Convert the pressure to :
myrzilka [38]
21.5010667479427 I goth this asnswer cause I divided I think that's how u do it
5 0
3 years ago
the mass of a liquid is 11.50 g and its volume is 9.03 mL. How many significant figures should its density value have?
BlackZzzverrR [31]

Answer:

3

Explanation:

The mass has 4 sig digits.

The volume has 3 sig digits

The density is = 11.50/9.03 = 1.2735

To 3 sig digits (determined by 9.03) the answer would be 1.27 gram/mL

6 0
3 years ago
The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?
vazorg [7]
C + O2= CO2
n  =  \frac{m}{mw}
n =  \frac{5.4}{12}  \\ n  = 0.45 \: mol \: of \: carbon
n =  \frac{13.6}{12 + 16 \times 2} \\ n =  \frac{13.6}{44}  \\ n = 0.31 \: mol \: of \: carbon \: dioxide
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %
4 0
3 years ago
...................................................................Help dying of boredem
zhannawk [14.2K]
Can we talk here?
I don’t have what you want to talk on
5 0
3 years ago
Read 2 more answers
05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
Other questions:
  • What does the law of conservation of matter/mass state
    13·2 answers
  • 1.what happens when vinegar and baking soda are passed through lime water?
    15·1 answer
  • Models may change as new discoveries are made. Please select the best answer from the choices provided T F
    13·1 answer
  • Convert the following temperatures to degrees Celsius or Fahrenheit: (a) 95°F, the temperature on a hot summer day; (b) 12°F,
    13·1 answer
  • What is an example of a cation<br><br> what’s an example of a cation
    9·2 answers
  • Which best describes an element ?​
    7·2 answers
  • Fish, amphibians, reptiles, birds, and mammals have similar embryos. They all start with gill slits. Fish and some amphibians gr
    5·1 answer
  • 880.7 decameters<br> as hectometers
    12·1 answer
  • BRAINLIEST IF CORRECT (PLEASE HURRY)
    14·2 answers
  • Can some one help whith these
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!