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Mashutka [201]
3 years ago
5

What is the structure of carbon

Chemistry
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

Explanation:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

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The first one and second one please
julia-pushkina [17]
The mass of the corn oil is 217.63 g. The density is 1.98 g/cm^3
3 0
3 years ago
What type of bond is Cl and Br?​
iogann1982 [59]

Answer: Polar bond

Explanation:

6 0
3 years ago
The equilibrium-constant expression for a reaction written in one direction is the __________ of the one for the reaction writte
VLD [36.1K]

Answer:

  • <u>    reciprocal   </u>

Explanation:

The <em>equilibrium constant</em> for an <em>equilibrium reaction </em>is the ratio of the equilibrium constant for the forward reaction, Kf, to the equilibrium constant for the reverse reaction, Kr:

  • For A ⇄ B

  • The forward reaction is: A → B, with rate constant is Kf = K₁ and
  • The reverse reaction is: B → A, with rate constant Kr = K₂

            K_{eq}=\dfrac{K_f}{K_r}=\dfrac{K_1}{K_2}

When you write the reaction in the other reaction, the forward and the reverse reaction are exchanged:

  • For B ⇄ A

  • The forward reaction is B → A, with rate constant Kf = K₂
  • The reverse reaction is A → B, with rate constant Kr = K₁

             

             K'_{eq}=\dfrac{K_f}{K_r}=\dfrac{K_2}{K_1}

As you see:

          K'_{eq}=\dfrac{1}{K_{eq}}

Thus, <em>the equilibrium-constant expression for a reaction written in one direction is the </em><em><u>    reciprocal</u></em><em>___</em><em> of the one for the reaction written for the reverse direction.</em>

8 0
4 years ago
The mass of an average blueberry is 0.75 g and the of am automoblie is 2.0 x 10 to the 3 Kg. Find the number of automobiles whos
Paul [167]

Answer : The number of automobiles needed are, 2.26\times 10^{17}

Explanation :

First we have to calculate the mass of blueberries.

As, 1.0 mole of blueberries contains 6.022\times 10^{23} blueberries

So, 0.75 grams of blueberries contains 0.75g\times 6.022\times 10^{23}=4.52\times 10^{23}g blueberries

Mass of blueberries = 4.52\times 10^{23}g

Now we have to calculate the number of automobiles needed.

Number of automobiles needed = \frac{4.52\times 10^{23}g}{2.0\times 10^{3}kg}

Number of automobiles needed = \frac{4.52\times 10^{23}g}{2.0\times 10^{3}\times 10^{3}g}

Number of automobiles needed = 2.26\times 10^{17}

Thus, the number of automobiles needed are, 2.26\times 10^{17}

8 0
3 years ago
PLZ help me with this question
Karo-lina-s [1.5K]
Mean: 237.5
Median: 250
Mode: 300
4 0
3 years ago
Read 2 more answers
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