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Elis [28]
1 year ago
9

WILL GIVE BRAINIEST ANSWER A chemical equation has different numbers of atoms on the left and right sides.

Chemistry
1 answer:
Alinara [238K]1 year ago
4 0

Answer:

Unbalanced

Explanation:

You need to have the same number of atoms on both sides for it to be balanced

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Chemistry, please help
Luba_88 [7]

Answer:

Name ; Nickel(ii)Hydroxide

Formula;NI3O6

               

Explanation:

3 0
3 years ago
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Lelechka [254]

Answer:

ΔG°rxn = -69.0 kJ

Explanation:

Let's consider the following thermochemical equation.

N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ

Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.

3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ

8 0
3 years ago
List three factors thatinfluence the rate at whick dissolving occurs
lys-0071 [83]
1) Temperature (heat) of the solution
2) Concentration (amount) of both solvent (usually water) and solute (substance being dissolved by solvent)
3) Movement (kinetic energy) of the solution, as in shaking/stirring
5 0
3 years ago
Antoine Lavoisier burned metals in sealed jars. What is your prediction of his experimental results?
Aliun [14]

Answer:

The mass of the jar and contents remained the same after the metal was burned.

Explanation:

My prediction about the experimental results is that  the mass of the jar and contents remained the same after the metal was burned in the jar.

This is compliance with the law of conservation of mass which states that in a chemical reaction, matter is neither created nor destroyed by bonds are rearranged for new compounds to form.

  • In compliance with this law, it is expected that the mass of the jar and its content will remain the same before and after the reaction.
  • No new material was added and no material was removed from the jar.
8 0
3 years ago
The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Otrada [13]

Answer:

25.2 kJ

Explanation:

The complete question is presented in the attached image to this answer.

Note that, the heat gained by the 2.00 L of water to raise its temperature from the initial value to its final value comes entirely from the combustion of the benzoic acid since there are no heat losses to the containing vessel or to the environment.

So, to obtained the heat released from the combustion of benzoic acid, we just calculate the heat required to raise the temperature of the water.

Q = mCΔT

To calculate the mass of water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat capacity of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

From the graph,

Final temperature of water = 25°C

Initial temperature of water = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
3 years ago
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