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EastWind [94]
3 years ago
10

What is Ka for H3PO4(aq) ⇌ H+(aq) + H2PO4-(aq) a. Ka = (H3PO4)/(h+)(H2PO4-) B. Ka = (H3PO4)(H+)(H2PO4-) C. Ka = (H3PO4)/(H+)(H2P

O4-) D. Ka = (H+)(H2PO4-)/(H3PO4)
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

The answer is option d.

Ka = (H+)(H2PO4-)/(H3PO4)

Hope this helps.

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Use the Nernst equation to calculate the concentration of the unknown solution. Base this on your experimental voltage of 1.074
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Answer:

0.3793 M

Explanation:

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1.074  = 1.1 - 0.0592/2 log [Zn^2+]/0.050179

1.074 - 1.1 = - 0.0592/2 log [Zn^2+]/0.050179

-0.026 = -0.0296  log [Zn^2+]/0.050179

-0.026/-0.0296 = log [Zn^2+]/0.050179

0.8784 =log [Zn^2+]/0.050179

Antilog(0.8784) = [Zn^2+]/0.050179

7.558 =  [Zn^2+]/0.050179

[Zn^2+] = 7.558 * 0.050179

[Zn^2+] = 0.3793 M

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