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Masja [62]
3 years ago
5

Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is

Chemistry
1 answer:
lions [1.4K]3 years ago
4 0
Carbon disulfide is prepared by heating sulfur and charcoal. the chemical equation is S2(g) + C(s) <---> CS2 (g) Kc = 9.40 at 900 K.
Hope this helps:)
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Which of the following is an example of a physical change? A) grinding coffee beans B) baking a cake C) converting water to hydr
lara [203]

Answer: A) grinding coffee beans

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

A chemical change is defined as a change in which a change in chemical composition takes place. A new substance is formed in these reactions.

1. Grinding coffee : Only change in size takes place, thus a physical change

2. Baking a cake: the chemical reaction occurs by combination of flour with oxygen , thus a chemical change.

3.:converting water to hydrogen and oxygen: The decomposition iof water takes place, thus is a chemical change

4.Burning of coal: the chemical reaction occurs by combination of carbon with oxygen , thus a chemical change.

5 0
3 years ago
In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2
inysia [295]

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

=50 g

Percentage composition :

  • Ca-calcium

\tt \dfrac{20}{50}\times 100\%=40\%

  • C-carbon

\tt \dfrac{6}{50}\times 100\%=12\%

  • O-oxygen

\tt \dfrac{24}{50}\times 100\%=48\%

3 0
3 years ago
Will alka-seltzer fizz when added to apple juice?
Naddik [55]
Yes but only if you're talking about treated apple juice with a naturally small amount of water mixed in.
4 0
3 years ago
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m
12345 [234]

<u>Answer:</u> The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For butane:</u>

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol

The chemical equation for the reaction of butane and oxygen gas follows:

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = \frac{13}{2}\times 0.224=1.456mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = \frac{10}{2}\times 0.224=1.12moles of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

8 0
3 years ago
What is the concentration (M) of sodium ions in 4.57 L of a 0.398 M Na3PO4 solution?
____ [38]

0.398=mol/4.57L. mol= 1.818. 1.818*3=5.456. 5.456/(4.57L)=1.19 M

5 0
3 years ago
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