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3 years ago

Challenge 1/7

Chemistry

2 answers:

Alexxandr [17]3 years ago

5 0

Answer:

If you could magically make two neutrons in the nucleus of an atom disappear, the atomic number and the electrical charge of that atom would remain unchanged. Neutrons do not carry an electrical charge so adding or removing them from the nucleus does not change the electrical charge of the nucleus.

Explanation:

LuckyWell [14K]3 years ago

4 0

Answer:

Not too sure but I think it's protons

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Ca:<br> alkali metal<br> alkaline earth metal<br><br> The answer is alkaline earth metal!

Alecsey [184]

Answer:

alkaline earth metal

it's because calcium in the periodic table is located in group 2

7 0

3 years ago

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An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 6.50 g of this compound produced 9.53 g o

OverLord2011 [107]

Answer:

There were 0.216 moles of oxygen in the sample

Explanation:

Step 1: Data given

Mass of compound = 6.50 grams

Mass of CO2 = 9.53 grams

Molar mass of CO2 = 44.01 g/mol

Mass of H2O = 3.90 grams

Molar mass H2O = 18.02 g/mol

Step 2: Calculate moles CO2

Moles CO2 = 9.53 grams / 44.01 g/mol

Moles CO2 = 0.217 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.217 moles CO2 we have 0.217 moles C

Step 4: Calculate mass C

Mass C = 0.217 moles C *12.01 g/mol

Mass C = 2.61 grams

Step 5: calculate moles H2O

Moles H2O = 3.90 grams / 18.02 g/mol

Moles H2O = 0.216 moles

Step 6: Calculate moles H

In 1 mol H2O we have 2 moles H

In 0.216 moles H2O we have 0.433 moles H

Step 7: Calculate mass H

Mass H = 0.433 moles * 1.01 g/mol

Mass H = 0.437 grams

Step 8: Calculate mass O

Mass O = 6.50 grams - 2.61 grams - 0.437 grams

Mass O = 3.453 grams

Step 9: Calculate moles O

Moles O = 3.453 grams / 16.0 g/mol

Moles O = 0.216 moles

There were 0.216 moles of oxygen in the sample

4 0

3 years ago

A student needs to prepare a stock solution for the lab - 500.0 ml of 0.750 m nitric acid. The student is provided with concentr

dlinn [17]

Molarity of concentrated nitric acid = 15.9 M

Volume of the stock solution to be prepared = 500.0 mL

Concentration of the stock that is to be prepared = 0.750 M

Calculating moles from molarity and volume of stock:

$500.0mL*\frac{1L}{1000mL}*0.750\frac{mol}{L} =0.375 mol HNO_{3}$

Calculating volume of concentrated nitric acid to be taken for the preparation of stock solution:

$0.375mol*\frac{1L}{15.9mol} =0.0236 L$

Converting L to mL:

$0.0236L*\frac{1000mL}{1L}$ = 23.6 mL

Volume of distilled water to be added to 23.6 mL of 15.9 M nitric acid to get the given concentration = 5000.0mL-23.6mL=976.4 mL

Therefore, 976.4 mL distilled water is to be added to 23.6 mL of 15.9 M nitric acid solution to prepare 500.0 mL of 0.750M nitric acid.

6 0

4 years ago

Please help me anyone its due today thank you !

Nina [5.8K]

true

Explanation:

Ecothermic reactiions are reactions or processes that release energy. From heat or light.

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3 years ago

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In which substance are the particles close together and slowly moving past each other? Air, Ice, Steam or Water?

damaskus [11]

I think the answer is water/ Liquid.

If it’s incorrect, I’m sorry

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3 years ago