1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Greeley [361]
4 years ago
10

Can someone please help me with this please❗️❗️❗️❗️❗️❗️❗️❗️

Physics
1 answer:
ICE Princess25 [194]4 years ago
4 0

Answer:

A the one that was thrown

B the one that was thrown

C the one that was just dropped

Explanation:

pl give brainliest

You might be interested in
An object with a mass of 78 kg is lifted through a height of 6 meters how much work is done
il63 [147K]
We got the following:
m = 78kg
h = 6m
g = 9.8 m/sec^{2} ≈ 10 m/sec^{2}
----------------------------------------------------------------------------
A = ?

As we know A = Ep = mgh    ->      potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule


5 0
3 years ago
A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle du
White raven [17]

Answer:

a. \phi _B=3.0528\times10^-^3T\ m^2\\ \\b. \phi_B=1.83299\times10^-^3T\ m^2\\\\c.\phi_B=0

Explanation:

#Consider a circular area of radius R=2.98cm in the xy-plane at z=0. This means all the are vector points toward the +ve z-axis.

a. first, find the magnetic flux if the magnetic field has a magnitude of B=0.23T and points toward the +ve z-axis. The angle between the magnetic field and the area is \theta=0. Hence the magnetic flux:-

\phi _B=\int {\bar B} . d\bar A \\=\int BdAcos(\theta)=BAcos(0)=BA\\\\=\pi R^2B=\pi(6.50\times10^-^3m)^2(0.230T)\\=3.0528\times10^-^3 T\ m^2

Hence flux magnitude in +z direction is 3.0528\times10^-^3T \ m^2

b. We now find the magnetic flux when the field has a magnitude of <em>B=0.230T</em> and points at an angle of \theta=53.1\textdegree from the +z direction.

Magnetic flux is calculated as:

\phi _B=\int\bar B \bar dA\\=\int BdAcos (\theta)=BAcos(0)=BA\\=\pi R^2B=\pi(6.50\times 10^-^2m)^2(0.230T)\\=1.83299\times 10^-^3 T \ m^2

Hence the flux at an angle of 53.1\textdegree is 1.83299\times 10^-^3T \ m^2

c. We now need to find the magnetic flux if the field has a magnitue of B=0.230T and points in the direction of +y-direction. As with the previous parts, the magnetic flux will be calculated as:

\phi_B= \int\bar B \times d\bar A\\=\int BdAcos(\theta)\\=BAcos(90\textdegree)\\=0

Hence the magnetic flux in the +y-direction is zero.

3 0
3 years ago
An object example to decrease pressure.
Olin [163]

Answer:

To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.

3 0
4 years ago
Read 2 more answers
D) A tank with dimensions: 3m x 2m x 2m contains water upto its half
lorasvet [3.4K]

Answer:

P = 9800 [Pa]

Explanation:

In order to calculate the pressure at the bottom, we must use the following formula.

P = Ro*g*h

where:

P = pressure [Pa] (units of pascals)

Ro = density of the water = 1000 [kg/m³]

g = gravity acceleration = 9.8 [m/s²]

h = height = 1 [m] (because its half of the portion, the full height is 2 m)

P = 1000*9.8*1

P = 9800 [Pa]

5 0
3 years ago
A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectiona
sweet [91]

Answer:

Y = 2.27 \times 10^{10} N/m^2

Explanation:

Natural length of the string is given as

L_o = 43 cm

length of the string while block is hanging on it

L = 53 cm

extension in length is given as

\Delta L = 10 cm

now we have strain in the string is given as

strain = \frac{\Delta L}{L}

strain = \frac{{10 cm}{43 cm}

strain = 0.23

similarly we will have cross-sectional area of the string is given as

A = 40 \times 10^{-6} m^2

now the stress in the string is given as

Stress = \frac{T}{A}

Stress = \frac{mg}{A}

Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}

stress = 9.07 \times 10^5 N/m^2

Now Young's Modulus is given as

Y = \frac{stress}{strain}

Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}

Y = 2.27 \times 10^{10} N/m^2

5 0
3 years ago
Other questions:
  • Calculate the total electric flux leaving the cubical surface formed by the six planes x, y, z = ±5 if the charge distribution i
    5·1 answer
  • Which is the following is a benefit of the water cycle to
    6·1 answer
  • When hoisting a personnel platform which of the following need not be engaged when they occupied platform is in a stationary pos
    6·1 answer
  • Convert 60 miles/hour to m/s (1.6km = 1mile; 1000m = 1km)
    8·1 answer
  • What type of wave interaction causes dead spots?
    6·1 answer
  • A pendulum is observed to complete 23 full cycles in 58 seconds. Use the definition of frequency to find the frequency.
    9·1 answer
  • A ball is thrown vertically upwards from the edge of a rooftop of a tall building. It passed a point 50 m below the rooftop afte
    6·1 answer
  • A 5 kg ball is sitting on top of a hill. It has a Potential Energy of 6000J. What is the height of the ball?​
    15·1 answer
  • !! Offering 50 points !!
    11·2 answers
  • A beam of monochromatic light is aimed at a slit of width and forms a diffraction pattern. In which case is the width of the cen
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!