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Leni [432]
3 years ago
15

Why should you use control while during an experiment?

Physics
1 answer:
Sergio039 [100]3 years ago
8 0
To provide a greater certainty that the observed results are not by chance.
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Which two terms indicate the same area of the body? *
Kruka [31]

Answer:

For example, the toes are anterior to the heel, and the popliteus is posterior to the patella. Superior and inferior, which describe a position above (superior) or below (inferior) another part of the body. For example, the orbits are superior to the oris, and the pelvis is inferior to the abdomen.

Explanation:

4 0
3 years ago
What causes diffferent air density?
ololo11 [35]

Answer:

The temperature and gravity both affects the density

5 0
3 years ago
two objects are in uniform circular motion at the same speed but at different radii. the ones with the __ radius has the largest
Cerrena [4.2K]

Answer:the one with the smaller radius has the highest centripetal force

Explanation:

5 0
3 years ago
Read 2 more answers
The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins
krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, \lambda=1.9\times 10^{-6}\ m

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

\lambda\propto \dfrac{1}{T}

or

\lambda=\dfrac{b}{T}

b = Wein's displacement constant

\lambda=\dfrac{2.93\times 10^{-3}}{T}

T=\dfrac{2.93\times 10^{-3}}{\lambda}

T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

3 0
3 years ago
What tension would you need to make a middle c (261.6 hz) fundamental mode on a 1 m string (for example, on a harp)? the linear
Allisa [31]
The frequency of middle C on a string is
f = 261.6 Hz.

The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
   = 0.002 kg/m

The length of the string is L = 1 m.

Let T =  the tension in the string (N).
The velocity of the standing wave is
v= \sqrt{ \frac{T}{\rho} }

In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
\sqrt{ \frac{T}{\rho} } =f \lambda = fL \\\\ \frac{T}{\rho} = (fL)^{2} \\\\ T = \rho (fL)^{2}

From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
   = 136.87 N

Answer: 136.9 N (nearest tenth)

4 0
3 years ago
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