Answer:
<h2>The coefficient of static friction will be
0.7</h2>
Explanation:
Given data
the radius of curve= 90m
speed v= 90 km/h to m/s = (90*100)/60*60= 25 m/s
we know that the expression for the centripetal force acting on the car
-------1
we also know that the expression for the frictional force between road and tire.
Ff= μmg--------2
Equating equation 1 and 2 we have
μmg= mv^2/r
μ= v^2/gr
substituting the values of speed and radius we have (assuming g= 9.81m/s^2)
μ= 25^2/9.81*90
μ= 625/882.9
μ= 0.7
If the two cars traveling opposite directions have the same mass, then yes, the momentum of a car traveling south will have the same momentum as a car traveling north at the same speed.
Answer:
Acceleration = 9.8 m/sec2
Explanation:
We know that the acceleration due to gravity is 9.8 m/sec2 near the surface of earth.
Remember that the gravity is always affecting everything on earth at every instant, even the rock at the very top of it's trajectory. It doesn't mind if the velocity is zero for an instant or if there's air resistance, the gravity force is there, and always aims towards the center of the earth.
So for all the trajectory of the rock, gravity is 9.8 m/sec2
Answer:
V = 1.1 m/s
Explanation:
given,
mass of railroad car 1 , m = 30,000. kg
travelling at the speed , u = 2.2 m/s
mass of car 2, M = 30,000. kg
initial speed, u' = 0 m/s
final speed of the car after collision, V = ?
using conservation of momentum
m u + M u' = (M+m)V
30000 x 2.2 + 0 = (30000 + 30000) V
60000 V = 66000
V = 1.1 m/s
he velocity of the two cars is equal to V = 1.1 m/s
