Two objects, A and B, are 10 m apart. Objects C and D are 20 m apart. The gravitational attraction between objects C and D is gr
2 answers:
Answer:
where , F = Gravitational force
G = Gravitational constant
= mass of first object
= mass of second object
r = distance between the two objects
As Gravitational force is inversely related to the distance between two objects, lesser is the distance , more will be the gravitational force. As distance between C and D is more , the force shoulld have been less. That means the product of the masses of the objects C and D is more than the product of the masses of the objects A and B.
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Answer:
t = 5.59x10⁴ y
Explanation:
To calculate the time for the ¹⁴C drops to 1.02 decays/h, we need to use the next equation:
(1)
<em>where : is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>
To find A₀ we can use the following equation:
(2)
<em>where N₀: is the initial number of particles of ¹⁴C in the 1.03g of the trees carbon </em>
From equation (2), the N₀ of the ¹⁴C in the trees carbon can be calculated as follows:
<em>where : is the tree's carbon mass,
: is the Avogadro's number and
: is the ¹²C mass. </em>
Similarly, from equation (2) λ is:
<em>where t 1/2: is the half-life of ¹⁴C= 5700 years </em>
So, the initial activity A₀ is:
Finally, we can calculate the time from equation (1):
I hope it helps you!