B. false pemdas kid get with it
Answer : D

The denominators are same
So we combine the numerators

To remove parenthesis we distribute negative sign inside the second parenthesis



Morgan made a mistake. He forgot to distribute the negative sign
Morgan forgot to distribute the negative sign to two of the terms 2t and 2 inside second parenthesis
Let his total money be x.
He spent (3/7)*x of his money.
He gave 1/4(x-3/7x) to his sister.
which is : (1/4)*(4/7)*x = (1/7)*x
Now,
How much money he have in the beginning =
(3/7)*x+(1/7)*x+120=x
(4/7)*x+120=x
120=x-(4/7)*x
120=(3/7)*x
x=120*7/3 [cross multiplication]
x=280.
So, Alex had $280 in the beginning.
Answer:
it stays the same until t=0, where it is undefined
Step-by-step explanation:
2t/t = 2 . . . . when t ≠ 0
2t/t = undefined when t = 0.
The value of t can increase or decrease and the value of the ratio remains the same. The value has a "hole" at t=0, where it is undefined. Otherwise, its value is always 2.