Determine the best name for the quadrilateral

Mathematics

1 answer:

NemiM [27]4 years ago

8 0

Answer:

this is a paralleogram

Step-by-step explanation:

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Solve the inequality, -4 less than 4(6y-12)-2y

erastova [34]

-4 < 4(6y - 12) - 2y

Distributive property.

-4 < 24y - 48 - 2y

Combine like terms.

-4 < 22y - 48

Add 48 to both sides.

44 < 22y

Divide both sides by 22.

2 < y

The value of y is greater than the value of 2.

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3 years ago

Round 10,982 to the nearest thousand

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3 years ago

A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t

Georgia [21]

Part 1:

For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

Part 2:

For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds

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4 years ago

If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a

galina1969 [7]

Answer:

Both objects collide at t=3 in the point <9,9,9>

Step-by-step explanation:

Collision Of Moving Objects

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

$r1(t)=$

$r2(t)=$

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

$t^2=4t-3$