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3 years ago

If f(x) = e^[3ln(x^2)], then f'(x) = ?

Mathematics

2 answers:

kherson [118]3 years ago

8 0

You might need to give out the choices, if there are any. thanks for asking.

loris [4]3 years ago

4 0

The correct answer to this question is 6x^5. For the solution, d/dx e^(3ln(x²)). It will be d/dx x^6. So the answer will be = 6x^5. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.

You might be interested in

F(x) = 5x - 3 for x = -7

erastovalidia [21]

Answer:

Step-by-step explanation:

f(-7) = 5(-7) - 3 = -35 - 3 = -38

6 0

3 years ago

(y - 2)2 = y2 – 6y + 4 Is this statement true or false?

trasher [3.6K]

<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0

2 years ago

Read 2 more answers

Solve the equation: \frac{2}{3}t=\frac{5}{9} (hint: reciprocal)

Aleks04 [339]

Given:

$\frac{2}{3}t=\frac{5}{9}$ $\text{ We know that the reciprocal of }\frac{2}{3}\text{ is }\frac{3}{2}\text{.}$

Multiply both sides by 3/2, we get

$\frac{3}{2}\times\frac{2}{3}t=\frac{3}{2}\times\frac{5}{9}$

Cancel out the common multiples, we get

$t=\frac{1}{2}\times\frac{5}{3}$

$t=\frac{1\times5}{2\times3}$

$t=\frac{5}{6}$

The solution of the given equation is

$t=\frac{5}{6}$

$t=0.8333.$

3 0

1 year ago

98 Points! MATH SOLVING SYSTEMS OF LINEAR EQUATIONS

photoshop1234 [79]

Answer:

40 Tickets

80 Tickets

Step-by-step explanation:

To find how many tickets it will take to break even, we use the formula:

$Break Even In Units = \dfrac{FixedCost}{SalesPricePerUnit-VariableCost}$

Our variables are:

Fixed Cost = $200

Sales Price = $10

Variable Cost = $5

Let's plug in our values into the formula.

$Break Even In Units = \dfrac{200}{10-5}$

$Break Even In Units = \dfrac{200}{5}$

$Break Even In Units = 40$

So the class needs to sell a total of 40 Tickets to break even.

Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.

Number of tickets for $200 profit = 40 x 2

Number of tickets for $200 profit = 80 Tickets.

So the class needs to sell 80 Tickets to make a $200 Profit.

5 0

3 years ago

These ordered pairs, {(2,4) (3,6) (4,8) (5,10)}, are a function. True False

ki77a [65]

Answer:

True

Step-by-step explanation:

In order for a relation (a set of ordered pairs) to be considered a function, every value in the domain (the set of all the first numbers in the pair) is associated with one value in the range (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if every value in the domain only has one arrow coming out of it. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.

8 0

3 years ago