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levacccp [35]
3 years ago
6

If f(x) = e^[3ln(x^2)], then f'(x) = ?

Mathematics
2 answers:
kherson [118]3 years ago
8 0
You might need to give out the choices, if there are any. thanks for asking.
loris [4]3 years ago
4 0
The correct answer to this question is 6x^5. For the solution, d/dx e^(3ln(x²)). It will be d/dx x^6. So the answer will be = 6x^5. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.  
You might be interested in
Which of the following is not a Pythagorean triple?. . A.. 28, 45, 53. B.. 16, 63, 65. C.. 13, 84, 85. D.. 11, 61, 62.
Anna11 [10]
A set of numbers is said to be Pythagorean triple if the sum of the squares of the lesser numbers equal the square of the remaining number,

A. 28² + 45² = 2809    ;  53² = 2809     ; EQUAL
B. 16² + 63² = 4225    ;  65²= 4225      ; EQUAL
C. 13² + 84² = 7225    ;  85² = 7225     ; EQUAL
D. 11² + 61² = 3842    ;   62² = 3844     ; NOT EQUAL

The answer is letter D.
6 0
2 years ago
Read 2 more answers
What is the solution of the equation 9^2x=6? Round your answer to the nearest ten-thousandth.
sammy [17]

Answer:

0.4077

Step-by-step explanation:

It's important to use parenthesis to avoid confusion.

9^(2x) = 6

Use exponent properties:

(9^2)^x = 6

81^x = 6

Take log of both sides

ln(81^x) = ln(6)

Use log properties:

x ln(81) = ln(6)

Solve for x:

x = ln(6) / ln(81)

x ≈ 0.4077

4 0
2 years ago
1. Input
wel

Answer:

The equilibrium point represents the raising or lowering the price in response to changes in the supply or demand.

If the price of a good is above equilibrium, this means that the quantity of the good supplied exceeds the quantity of the good demanded.

If the quantity is below the equilibrium point, it will create a shortage. because the quantity supplied is less than quantity demanded.

Hope this helps!

Step-by-step explanation:

7 0
3 years ago
Please use the figure below to solve for both x and y
kkurt [141]

Answer:

x=10°

y = 12°

Step-by-step explanation:

<TSV = 5x + 4x = 90°

=> 9x = 90°

Divide by 9,

x = 10°

<RSU = 10y + 10° + 5x = 180°

=> 10y + 10° + 5*10° = 180°

=> 10y + 10° + 50° = 180°

=> 10y + 60° = 180°

Subtract 60° on both sides,

10y = 180° - 60° = 120°

Divide by 10,

y = 120° / 10 = 12°

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
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