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3 years ago

Which of the following expressions are equivalent to 1/5x? mark all that apply.

Mathematics

1 answer:

konstantin123 [22]3 years ago

7 0

3/15x, 2/10x and 0.20x are equivalent to 1/5x

Step-by-step explanation:

Step 1: Verify whether the expressions are equal to 1/5x

⇒ 3/15x = 1/5x (Common factor is 3)

⇒ 2/10x = 1/5x (Common factor is 2)

⇒ 0.50x = 1/2x Not equivalent to 1/5x

⇒ 0.20x = 1/5x (Decimal equivalent)

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Simplify ech answer into a fraction, Show all work please!

Gnom [1K]

Answer:

the first one is -9/40. the second one is 109/20. the third one is -8/35.

Step-by-step explanation:

here is the work for the first one 3/8-.6 and convert into a simplified fraction and came up with -9/40. here is the work for the second one 4 4/3+0.7 and then convert into a simplified fraction and came up with 109/20. here is the work for the third one 4/7-0.8 and then convert into a simplified fraction and came up with -8/35.

6 0

3 years ago

Can any kind soul help me ASAP!

CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172 Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6= $\frac{167*x+3038}{19+x}$

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

3 0

3 years ago

Please help me with this

Gnoma [55]

Given:

The equation is:

$3^x\times 9=3^{2n-1}$

To find:

The value of n in terms of x.

Solution:

We have,

$3^x\times 9=3^{2n-1}$

It can be written as

$3^x\times 3^2=3^{2n-1}$

$3^{x+2}=3^{2n-1}$ $[\because a^ma^n=a^{m+n}]$

On comparing the exponents, we get

$x+2=2n-1$

Add 1 on both sides.

$x+2+1=2n-1+1$

$x+3=2n$

Divide both sides by 2.

$\dfrac{x+3}{2}=n$

Therefore, the value of n is terms of x is $n=\dfrac{x+3}{2}$ .

7 0

3 years ago

Cdef maps to jklm with the transformation (x,y) to (4x,4y) to (x-4,y-9). What is the value of ef/lm.

Elina [12.6K]

Answer:

EF / LM = 1 / 4

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.

Dilation is the enlargement or reduction in the size of a figure. If a point A(x, y) is dilated by a scale factor of k, the new point is at A'(kx, ky).

Translation is the movement of a point right, left, up or down. If a point A(x, y) is translated a units left and b units down, the new point is at A'(x - a, y - b).

Translation preserves the size and shape of an object. Dilation preserves the shape but not the size.

Cdef maps to jklm with the transformation (x,y) to (4x,4y) to (x-4,y-9).

CDEF was first dilated by a scale factor of 4 to get (4x,4y) before it was translated by (x-4,y-9). Since dilation changes the size of the figure, hence JKLM would be 4 times the size of CDEF. Therefore:

LM / EF = 4

EF / LM = 1 / 4

6 0

3 years ago

1½ hours is how much in seconds??

Ne4ueva [31]

3/2=1.5 hour=5400 second

Hope it helps you

8 0

3 years ago

Read 2 more answers