A wedding ring costs £13000. Work out the price after a 11% increase

Mathematics

2 answers:

Tomtit [17]3 years ago

8 0

Answer:

14430 pounds

Step-by-step explanation:

Given that:

cost of ring: 13000

percentage increase: 11%

So, to find the new cost, we have to find the increase cost, in pounds:

11 / 100 times 13000 = 1430 pounds.

NOW to calculate the new cost, we add the increase cost to the original:

13000 + 1430 = 14430

Please mark brainiest

olga2289 [7]3 years ago

7 0

When £13000 is increased by 11% the new value becomes to £14430

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Is a relation always a function? Is a function always a relation? Explain.

katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.

In fact, every function is a relation. However, not every relation is a function. A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

Which means whatever a function occurs, it will be a relation from one set to other.

But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0

3 years ago

9.50 One way to evaluate the effectiveness of a teaching assistant is to examine the scores achieved by his or her students on a

EleoNora [17]

Answer:

Step-by-step explanation:

Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

$H_0: s^2 = 300\\H_a: s^2 \neq 300$