15, if you plot the points, then seperate the x and y into two seperate lines, you can create a 3,4,5 triangle to find the distance between the points.

4 0

3 years ago

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The width of a rectangle is the length minus 2 units. the area of the rectangle is 35 units

Mariana [72]

Answer:

$Length=7units\\\\Width=5units$

Step-by-step explanation:

Width=(Length-2) units

W=(L-2) units

Area of the rectangle= 35 square units

Area = length* Width

$35= L*(L-2)\\\\35=L^2-2L$

Subtracting 35 both sides:

$L^2-2L-35=0$

Solving the quadratic equation for 'L' ;

Using factorization:

$L^2+5L-7L-35=0$

Taking common from the equation :

$L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5$

$L-7=0\\\\L=7$

The length cannot be negative, therefore Length(L)= 7

$Width=Length-2\\\\=7-2\\\\=5 units$

$Length=7units\\\\Width=5units$

8 0

3 years ago

The length of a rectangle is 5 inches shorter than double its width. The perimeter of the rectangle is 192 inches. Write a two-s

alukav5142 [94]

Answer:

Step-by-step explanation:

Givens

Let the width = x

Let the length = x + 5

Equation

2w + 2W = P

Solution

2x + 2(x + 5) = 192 Remove the brackets <=== Answer

2x + 2x + 10 = 192 Combine like terms

4x + 10 = 192 Subtract 10 from both sides

4x = 192 - 10

4x = 182 Divide by 4

4x/4 = 182/4

x = 45.5

8 0

3 years ago