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ss7ja [257]
2 years ago
14

Which expression is equal to 527.471?*

Mathematics
1 answer:
stepan [7]2 years ago
5 0

Answer:

Step-by-step explanation:

527.471 =(5 ×100.000) +(2 ×10.000) +(7 ×1.000) +(4 ×100) +(7 ×10) +(1×1)

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If the ratio of radius of two spheres is2:3 what is the ratio of their volumes​
labwork [276]

Answer:

8:27

Step-by-step explanation:

1 way to do it is...

The volume of a sphere is 4/3*pi*r^3. Plugging in 2 and 3 in for the radii you get the volumes are about 33.51 and 113.1, which is an 8:27 ratio.

Another way to do it is...

The ratio of the radii is 2:3 and a radius is 1-dimensional. The volume, however is 3-dimensional. To get from 1-D to 3-D, you have to cube the numbers. 2^3 is 8 and 3^3 is 27, so the ration is 8:27.

3 0
3 years ago
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Find the area of the following trapezoid
erik [133]

Answer:

12

Step-by-step explanation:

4 0
2 years ago
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Let me help you out have some points <br> and wash your hands
worty [1.4K]

Answer:

Thank you have fun in quarantine

7 0
3 years ago
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A factory is fabricating seats for minor-league baseball stadium. The stadium holds 7500 individuals in the factory can fabricat
SSSSS [86.1K]

Answer:

23 days

Step-by-step explanation:

We are told that the stadium holds 7500 individuals.

Now, if 600 seats have already been made, It means the number of seats left to be made to complete the stadium = 7500 - 600 = 6900 seats

We are told that 300 seats can be made in a day. Thus, number of days to be used to finish the remaining seats = 6900/300 = 23 days

Thus, it will take 23 days to complete all the 7500 seats.

5 0
3 years ago
A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0
3 years ago
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