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3 years ago

Which expression is equal to 527.471?*

Mathematics

1 answer:

stepan [7]3 years ago

5 0

Answer:

Step-by-step explanation:

527.471 =(5 ×100.000) +(2 ×10.000) +(7 ×1.000) +(4 ×100) +(7 ×10) +(1×1)

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If the ratio of radius of two spheres is2:3 what is the ratio of their volumes

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Answer:

8:27

Step-by-step explanation:

1 way to do it is...

The volume of a sphere is 4/3*pi*r^3. Plugging in 2 and 3 in for the radii you get the volumes are about 33.51 and 113.1, which is an 8:27 ratio.

Another way to do it is...

The ratio of the radii is 2:3 and a radius is 1-dimensional. The volume, however is 3-dimensional. To get from 1-D to 3-D, you have to cube the numbers. 2^3 is 8 and 3^3 is 27, so the ration is 8:27.

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A factory is fabricating seats for minor-league baseball stadium. The stadium holds 7500 individuals in the factory can fabricat

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Answer:

23 days

Step-by-step explanation:

We are told that the stadium holds 7500 individuals.

Now, if 600 seats have already been made, It means the number of seats left to be made to complete the stadium = 7500 - 600 = 6900 seats

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3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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3 years ago