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algol13
3 years ago
9

7-3 draw a diagram And find the difference

Mathematics
1 answer:
Wittaler [7]3 years ago
3 0
The answer is 4, to draw a diagram right 7 with a -4 below it. Cross the two out with line and right 3.
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The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.
natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

a) P_X(0) = \frac{e^{-3}3^0}{0!} = e^{-3} =  0.05

b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

P_X(0) = e^{-15}

P_X(1) = e^{15}*15

P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}

As a result,

P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308

Practically 0

4 0
2 years ago
Is 4kg greater than 4000g
antiseptic1488 [7]

Answer:

Nope they are the exact same

6 0
3 years ago
Read 2 more answers
The Area Ratio of two similar solids is 169: 289. If the volume of the smaller solid is 689,858 cm, what is the volume of the la
masha68 [24]

Answer:

1,542,682 cm^3.

Step-by-step explanation:

The scale factor = √169:√289

= 13:17

So the Volume ratio is 13^3:17^3

So the volume of the larger solid is  689,858 * (17^3/13^3)

= 1,542,682 cm^3.

5 0
3 years ago
I need to find the GCF and solve to get the right answer. And ASAP if ossicle please
BartSMP [9]

I just know the greatest common factor is 2ab

But i don’t know if it is foil method but I still don’t know how to put it in that format

6 0
3 years ago
Now solve in simplest terms: 4/5+4/5<br> please help no links or files
xxTIMURxx [149]

Answer:

1 and 3/5

Step-by-step explanation:

4/5+4/5=8/5

8÷5

=1 3/5

8 0
2 years ago
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