Answer:
Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !
Step-by-step explanation:
evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...
Answer:
2x(x + 3)(2x - 1)
Step-by-step explanation:
Given
4x³ + 10x² - 6x ← factor out 2x from each term
= 2x(2x² + 5x - 3) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 3 = - 6 and sum = + 5
The factors are + 6 and - 1
Use these factors to split the x- term
2x² + 6x - x - 3 ( factor the first/second and third/fourth terms )
= 2x(x + 3) - 1(x + 3) ← factor out (x + 3) from each term
= (x + 3)(2x - 1)
Thus
4x³ + 10x² - 6x = 2x(x + 3)(2x - 1) ← in factored form
Answer:
a:x=-3
c:x=1
Step-by-step explanation:
The zeros of a function are the values of x for which the value of the function f(x) becomes zero.
In this problem, we have the following function:
Here we want to find the zeros of the function, i.e. the values of x for which
In order to make f(x) equal to zero, either one of the factors 
or 
must be equal to zero.
Therefore, the two zeros can be found by requiring that:
1)
2)
So the correct options are
a:x=-3
c:x=1
Answer:
See below
Step-by-step explanation:
