Question

The perimeter of a rectangle sandpit is 40 meters. The length of the sandpit is 1 meter less than twice it’s width. What are the dimensions of this sandpit

Answer 1

Answer:

The width is 7 meters and the length is 13 meters

Step-by-step explanation:

The perimeter of a  rectangle sandpit is 40 meters.

Let the width be w units, then the length which is 1 meter less than twice it’s width becomes: $l=2w-1$

The perimeter of a rectangle is given by:

$P=2(w+l)$

We substitute P=40 and the length in term of w to get:

$40=2(w+2w-1)$

We simplify to get:

$40=2(3w-1)$

Divide through by 2 to get:

$20=3w-1\\\implies 21=3w\\\implies w=\frac{21}{3}=7$

Hence $l=2(7)-1=14-1=13$