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fredd [130]
3 years ago
8

Raquel establece que la rapidez del sonido en el aire en un día es de 346 m/s . Días después hace la misma medición obteniendo u

na rapidez de 340 m/ s . ¿Cuál será la temperatura del aire en cada día?
Physics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

La ecuación para la velodiad del sonido en aire esta dada por:

v = \sqrt{ \frac{\gamma*R*T}{M} }

Resolviendo esto para T, obtenemos:

T = v^2*(\frac{M}{\gamma*R} )

donde:

T = temperatura del aire en grados Kelvin

γ = constante adiabatica = 1.4

R = constante del gas ideal =

M = masa molar del aire = 29*10^(-3) kg/mol

Si sabemos que el primer día la velocidad es 346 m/s, tenemos:

v = 346 m/s

Ahora podemos reemplazar todos esos valores en la ecuación para T, y asi obtener:

T = (346m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 298.42 K

Para el segundo día la velocidad es 340 m/s, entonces ese día la temperatura va a ser:

T = (340m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 288.16 K

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