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olganol [36]
4 years ago
10

10 pounds . = how many ounces

Mathematics
2 answers:
nignag [31]4 years ago
7 0

Answer:

160oz

1lb=16oz

16*10=160

g100num [7]4 years ago
3 0

Step-by-step explanation:

there should be one ounces

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Daniella is solving 8/9 divided by 4. find her mistake and correct it.​
Korolek [52]

Answer:

the answer is 2/9.

Step-by-step explanation:

8/9÷4

= 8/9 × 1/4

= 8/36

=2/9

6 0
3 years ago
If m< DBG=58 and mDG =74 , find mGE
mestny [16]

Answer:

Option D: mGE = 190°

Step-by-step explanation:

From the property of angles of secant and tangent lines, we have:

DBG = (mGE - mDG)/2

(That is, the angle in point B is half the difference of the larger arc by the smaller arc defined by the lines)

So, we have that:

58 = (mGE - 74)/2

2*58 = mGE - 74

mGE = 116 + 74 = 190°

So we have that mGE is equal to 190°, correct option: D.

5 0
3 years ago
Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
The circumference of super eight is four times the conference at Circle B which statement about the areas of the circle is true
ICE Princess25 [194]
When you have factors in shapes you must remember:
circumference and perimeter are in one unit measures
area is in squared units
volume is in cubed units

So, when the circumference of A is 4 times that of C there is a factor of 4.
Since we need to know the area the factor 4 will change to a factor of 4² since area is a squared unit.

The solution is 4²=16, the are of circle A is sixteen times the area of circle B.
4 0
3 years ago
Holly missed 8 of 185 school days this year. Approximately what percent of school days was Holly in attendance?
natulia [17]
8/185 = 4.3 % 
That is the number of days she missed so she was in attendance

100-4 = 96%
3 0
3 years ago
Read 2 more answers
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