B) Use the graphs to solve the

Osborne invested $17,000 in stocks and bonds.

Pani-rosa [81]

SYSTEM OF EQUATIONS

S+B = 17000
0.1S+0.07B=1280

Multiply the first equation by 0.1 and subtract the second equation

0.03B=420
B=14,000
S=3,000

6 0

2 years ago

For the given function f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.

kakasveta [241]

Answer:

a) (f + g)(x) = 9x + 1

Domain: x ε R

b) (f - g)(x) = (-5x + 13)

Domain: x ε R

c) (f.g)(x) = 14x² + 37x - 42

Domain: x ε R

d) (f/g)(x) = (2x + 7)/(7x -6)

Domain: (x ε R except x = 6/7)

e) (f + g)(7) = 64

f) (f - g)(2) = 3

g) (f.g)(3) = 195

h) (f/g)(x) = 1/3

Step-by-step explanation:

f(x) = 2x + 7, g(x) = 7x - 6

a) (f + g)(x) = f(x) + g(x) = (2x + 7) + (7x - 6)

(f + g)(x) = 9x + 1

Since x is defined for functions f & g for all real numbers, the domain of (f + g)(x) is x ε R

b) (f - g)(x) = f(x) - g(x) = (2x + 7) - (7x - 6)

(f - g)(x) = (-5x + 13)

Since x is defined for functions f & g for all real numbers, the domain of (f - g)(x) is x ε R

c) (f.g)(x) = f(x) × g(x) = (2x + 7)(7x - 6)

(f.g)(x) = 14x² - 12x + 49x - 42 = 14x² + 37x - 42

Since x is defined for functions f & g for all real numbers, the domain of (f.g)(x) is x ε R

d) (f/g)(x) = f(x)/g(x) = (2x + 7)/(7x -6)

x is defined for functions f & g for all real numbers, the domain of (f/g)(x) will be x ε R except when the denominator vanishes (that is, goes to zero). This will cause the function to take up values of ∞.

This will happen when 7x - 6 = 0, x = 6/7.

Therefore, the domain of (f/g)(x) is x ε R except the point, x = 6/7.

e) (f + g)(7) = 9(7) + 1 = 64

f) (f - g)(2) = -5(2) + 13 = 3

g) (f.g)(3) = 14(3²) + 37(3) - 42 = 195

h) (f/g)(27) = (2(27) + 7)/(7(27) - 6) = 61/183 = 1/3

Hope this Helps!!!

5 0

2 years ago

The intersection of roads M and N creates a 41.4 degree angle. What are the complimentary and supplementary angles of this inter

Keith_Richards [23]

Supplementary angles are two angles which sum up to 180 degrees while complementary angled are those the sum is 90 degrees. Therefore, the complementary of 41.4 is 90-41.4 = 48.6 and the supplement would be 180-41.4= 138.6.

3 0

3 years ago

how many ways can Aileen choose 2 pizza toppings from a menu of 19 toppings if each topping can only be chosen one

alexdok [17]

Answer:

There are 342 different combinations.

Step-by-step explanation:

Ok, Aileen is choosing toppings for a pizza.

She can choose two.

There are 19 options that can be chosen once.

The first thing we need to do, is find all the "selections".

Here we have two selections:

Topping number 1

Topping number 2.

Now we need to find the number of options for each one of these selections:

Topping number 1: Here we have 19 options.

Topping number 2: Here we have 18 options (because one was already taken in the previous selection)

The total number of combinations is equal to the product between the numbers of options.

C = 19*18 = 342

There are 342 different combinations.

7 0

3 years ago

In the Salk vaccine field trial, 400,000 children were part of a randomized controlled double-blind experiment. Just about half

EastWind [94]

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

$\hat p_1 = \dfrac{57}{200000}$

= 0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

$\hat p_2 = \dfrac{142}{200000}$

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic can be computed as:

$Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}$

$Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}$

$Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}$

Z = - 6.03

P-value = 2P(Z < -6.03)

From the Z - tables

P-value = 2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

7 0

2 years ago