4x + 13y = 40
4x + 3y = -40
multiply second equation by -1
4x + 13y = 40
-4x - 3y = 40
add equations together
10y = 80
y = 8
put y in either original equation
4x + 3(8) = -40
4x + 24 = -40
subtract 24 from both sides
4x = 64
x=16
y=8
Answer:
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Step-by-step explanation:
There could be many answers for this question. In general, the number that comes after 16 is a number with 8 as the sum of its digits.
Explanation:
1st number 31 – Sum of digits is 3 + 1 = 4
2nd number 1031 – Sum of digits is 1 + 0 + 3 + 1 = 5
3rd number 402 – Sum of digits is 4 + 0 + 2 = 6
4th number 16 – Sum of digits is 1 + 6 = 7
Therefore, the missing number could be the single digit number 8 or any of the two-digit numbers 17, 26, 35, 44, 53, 62, 71 or 80. It could also be a bigger number with the digits of any of the given two-digit numbers and 0 for the other digits such as 260 or 7001.
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Answer:
(2,3)
Step-by-step explanation:
<u>x² - 4x - 5</u> <u>x² - 3x - 10</u>
(x - 5)(x + 1) (x - 5)(x + 2)
GCF: (x - 5)
LCM: (x - 5)(x + 1)(x + 2)
Answer: (x - 5)(x + 1)(x + 2)