All categories

3 years ago

URGENT PLEASE HELP ME

Mathematics

1 answer:

kvasek [131]3 years ago

5 0

Answer:

110in

Step-by-step explanation:

You are given the angle and the length of one leg of the triangle. Therefore, you will want to use one of the trigonometric formulae you've learnt. The available ones are:

$sin(\theta)=\frac{O}{H}\\cos(\theta)=\frac{A}{H}\\tan(\theta)=\frac{O}{A}\\$

where O represents the leg opposite the angle, A represents the leg Adjacent to the angle, and H represents the hypotenuse. The lamppost in this problem is the leg opposite the angle, so you want a formula that has O in the equation, namely sin or tan. Because you were given the leg adjacent to the angle, it makes sense here to use tan. Set up the equation as such to solve:

$tan(70)=\frac{x}{40}\\40*tan(70)=x\\x=110\\$

For some reason, it wanted you to convert 70 degrees to radians, so that may have been where you could have run into issues. If you plugged in 70 as degrees, you would get 48 which isn't an option. Converting 70 to 1.22 rad gets you the answer of 110 in.

You might be interested in

What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x

Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1/6 and the point (6, -2)

$y-\left(-2\right)=\frac{1}{6}\left(x-6\right)$

$y+2=\frac{1}{6}\left(x-6\right)$

subtract 2 from both sides

$y+2-2=\frac{1}{6}\left(x-6\right)-2$

$y=\frac{1}{6}x-3$

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

5 0

3 years ago

Please help me its a propotional question and answer of Z Y X

tino4ka555 [31]

Since the only two corresponding side you have are 10 units and 4 units, you can divide these two numbers to get the scale factor.

10÷4=2.5

next you find the sides corresponding to X Y and Z and if it is on the bigger figure you divide, if it is on the smaller side you multiply

X corresponds with 5 (so ×2.5)
Y corresponds with 8 (÷2.5)
Z corresponds with 10 (÷2.5)

final answer is X=12.5 Y=3.2 Z=4

I try to explain the question and give the answer, I hope this helps!

5 0

3 years ago

Find the value if S (s-6)squared= 75

Stels [109]

9...
75 + 6 = 81
The square root of 81 = 9

6 0

3 years ago

If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?

Ierofanga [76]

Answer:

it's -4 I just took the test and you will get it write

6 0

3 years ago

Find the difference. 6rs – (-2rs)

lilavasa [31]

There is no difference, 6rs-(-2rs) if you get rid of the parenthesis you are left with 6rs- -2rs and two negatives make a positive therefore the answer will become 8rs... I hope this helps :)

8 0

3 years ago