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8_murik_8 [283]
2 years ago
14

Find all x and y intercepts of the graph of the function f(x)= 2x^3+6x^2-2x-6

Mathematics
1 answer:
topjm [15]2 years ago
4 0

9514 1404 393

Answer:

  • y-intercept: (0, -6)
  • x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

  f(x) = (2x^3 +6x^2) -(2x +6)

  f(x) = 2x^2(x +3) -2(x +3)

  f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

You might be interested in
Find m∠STU and m∠TUA
PIT_PIT [208]

Answers:

  • angle STU = 65 degrees
  • angle TUA = 123 degrees

=========================================================

Explanation:

Let's find the expression for angle TUS in terms of x

Angle TUA has the expression 11x+2. It will add to angle TUS to get 180 degrees

(angle TUS) + (angle TUA) = 180

angle TUS = 180 - (angle TUA)

angle TUS = 180 - (11x + 2)

angle TUS = 180 - 11x - 2

angle TUS = -11x + 178

Now focus on the interior angles of triangle TUS. We have these three angles

  • T = 5x+10
  • U = -11x+178
  • S = 58

For any triangle, the interior angles always add to 180, so,

T+U+S = 180

(5x+10) + (-11x+178) + (58) = 180

(5x-11x) + (10+178+58) = 180

-6x + 246 = 180

-6x = 180-246

-6x = -66

x = -66/(-6)

x = 11

Use this x value to find the angle measures we're after:

  • angle STU = 5x+10 = 5*11+10 = 55+10 = 65 degrees
  • angle TUA = 11x+2 = 11*11+2 = 121+2 = 123 degrees

--------------------------

As an alternative route, you can apply the remote interior angle theorem. This says that adding two interior angles leads to the exterior angle that isn't adjacent to either one.

In this case, we would say

(angle STU) + (angle TSU) = angle TUA

that leads to the equation

(5x+10) + (58) = 11x+2

Solving this should lead to x = 11 to generate the angles mentioned earlier.

6 0
3 years ago
Help me plz idk how
Alika [10]
Hello there,

For problem one 
The mile is an appropriate unit to measure the distance run over a one-week period.

For problem two
The pound is an appropriate unit to measure the weight of a bag of sugar.


For problem three
The yard is an appropriate unit to measure the distance run on a football field.

Hope this helps!

8 0
3 years ago
1.) Determine the type of solutions for the function (Picture 1)
NNADVOKAT [17]

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

4.) The given function is g(x) = (-2/5)·(x - 4)² + 6

The parent function of a quadratic equation is y = x²

A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

7 0
2 years ago
Plz help me get the right answer to these ASAP
Kryger [21]

Hi!

\frac{1}{2} c > -1\\c > -2\\

Hope this helps!

7 0
3 years ago
Read 2 more answers
When n=1 there is 1 dot. when n=2 there are 3 dots, when n=3 there are 6 dots. notice that the total number of dots increases by
gayaneshka [121]

Answer:

<h3>Part A</h3>
  • d(n) = n(n + 1)/2
  • n = 1 ⇒ d(1) = 1(1 + 1)/2 = 2/2 = 1, proved
<h3>Part B</h3>
  • d(k) + (k + 1) =
  • k(k + 1)/2 + (k + 1) =
  • [k(k + 1) + 2(k + 1)]/2 =
  • [(k + 1)(k + 1 + 1)]/2 =
  • d(k + 1)
  • Proved

6 0
2 years ago
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