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3 years ago

What’s the cosine of

Mathematics

1 answer:

Vsevolod [243]3 years ago

4 0

Answer:

√23/√45 or √23/3√5

Step-by-step explanation:

Cosine is adjacent over hypotenuse. Angle W has an adjacent side of WU(√23) and WV .You know the adjacent but not the hypotenuse, so you will use the formula a^2+b^2=c^2 to find the hypotenuse. Plug in the sides for A and B -> (√23)^2+(√22)^2=c^2. Simplify it --> 23+22=c^2 --> 45=c^2. Solve for C alone (not c^2). √45=c. Then use the cosine formula (adjacent/hypotenuse) to plug in the numbers.

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Kameron has a combination of quarters and nickles in his wallet. The number of nickels is three times the number of quarters he

Aleksandr-060686 [28]

Answer:

Kameron has 5 quarters in his wallet

Step-by-step explanation:

Let

x----> the number of nickels

y----> the number of quarters

remember that

1 nickel=$0.05

1 quarter=$0.25

we know that

x=3y -----> equation A

0.05x+0.25y=2

Multiply by 100 both sides

5x+25y=200

Simplify

x+5y=40 -----> equation B

Substitute equation A in equation B

(3y)+5y=40

8y=40

y=5 quarters

x=3(5)=15 nickels

8 0

3 years ago

At the malt shop a large chocolate shake takes 8/9 of a pint of milk.If the medium shake takes 1/7 the amount of the large how m

jasenka [17]

There are several information's of immense importance in the problem. Based on these information's the answer to the question can be easily reached. The only thing that has to be kept in mind is the calculation part, otherwise it is a simple problem.
Now it is given that:
A large chocolate shake takes 8/9 of a pint of milk.
Then
Amount of milk required to make medium shake = (8/9) * (1/7) of a pint
= 8/63 of a pint
Then it can be said that for making a medium chocolate shake , 8/63 of a pint of milk is required. This is the simplest form of the fraction and it cannot be expressed as a mixed number since the denominator is higher than the numerator.

7 0

3 years ago

Please help me with this

Lana71 [14]

Answer:

Definition of mid-point

Step-by-step explanation:

Midpoint is the center point of a line segment

At midpoints the line segment is divided into two equal lengths

Point K is the midpoint of segment MJ and length of segment MK = length of segment KJ

Point K is the midpoint of segment OL and length of segment OK = length of segment KL

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