40/24+9/24= 40+9/24 = 49/24
Answer:
A) A[p(t)] = 36πt²
B) 7234.56 square units
Step-by-step explanation:
<u>Given functions</u>:

<u>Part A</u>
To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):
![\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%28p%29%20%26%20%3D%20%5Cpi%20p%5E2%5C%5C%5C%5C%20%5Cimplies%20A%5Bp%28t%29%5D%20%26%20%3D%20%5Cpi%20%5Bp%28t%29%5D%5E2%5C%5C%26%20%3D%20%5Cpi%20%286t%29%5E2%5C%5C%26%20%3D%20%5Cpi%206%5E2%20t%5E2%5C%5C%26%20%3D%2036%5Cpi%20t%5E2%5Cend%7Baligned%7D)
<u>Part B</u>
Given
Substitute the given values into the equation for A[p(t)} found in part A:
![\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%5Bp%288%29%5D%20%26%20%3D%2036%5Cpi%20t%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%208%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%2064%5C%5C%26%20%3D%20113.04%20%5Ccdot%2064%5C%5C%26%20%3D%207234.56%5C%3A%5C%3A%20%5Csf%20square%5C%3Aunits%5Cend%7Baligned%7D)
Therefore, the area of spilled paint after 8 minutes if 7234.56 square units.
Answer:
138 pounds
Step-by-step explanation:
Let the required weight of the patient be x pounds.
We have that,
156 milligrams of medicine is required for a patient weighing 104 pounds.
Then, 207 milligrams of medicine will be required for a patient having weight as shown below,
Weight of the patient = 
i.e. x = 
i.e. x = 
Hence, the patient needing 207 milligrams of medicine will have the weight 138 pounds.
Answer:
(x - 2) (x - 6)
Step-by-step explanation:
Factor the following:
x^2 - 8 x + 12
The factors of 12 that sum to -8 are -2 and -6. So, x^2 - 8 x + 12 = (x - 2) (x - 6):
Answer: (x - 2) (x - 6)
Answer:
If the length of a tree's shadow is 35.25 meters. The height of the tree to the nearest hundredth of a meter will be : 11.74m
Given:
Denora height=1.35 meters
Length =35.25 meters
Width =31.2 meters
Height of the tree=x
Proportion:
1.35 : 35.25 :: x : 31.2
Now let's determine the height of the tree:
35.25 - 31.2 / 1.35 = 35.25 / x
4.05 / 1.35 = 35.25 / x
Cross multiply
4.05x = 35.25 × 1.35
4.05x = 47.58
Divide both sides
x = 47.58 / 4.05
<u>x = 11.74</u>
In conclusion, if the length of a tree's shadow is 35.25 meters. The height of the tree to the nearest hundredth of a meter will be: 11.74m