Answer:
The correct option is 1 and 4 are correct.
Step-by-step explanation:
The dilation is the enlargement and comparison of a figure according to the scale factor from the given center of dilation.
The rule DO,2(x,y)(2x,2y) express the dilation with factor 2 and the center of dilation is origin. It shows the enlargement of the triangle. The sides of image is twice of the preimage.
In dilation the corresponding angles remains same and the corresponding sides are equal.
Therefore option 1 and 4 are correct.
Since all the variables cancel out and the coefficient equal to eachother, this system of equation has
<u>infinitely many solutions!</u>
9514 1404 393
Answer:
(x, y, z) = (1, 2, 3)
Step-by-step explanation:
The equations that result from reduction to row-echelon form are ...
x = 0.4 +0.2t
y = 5.6 -1.2t
z = t
Then t must have a value 5n+3 for 0 ≤ n < 1. That is, t=3.
x = 0.4 +0.2(3) = 1
y = 5.6 -1.2(3) = 2
z = 3
The integers that satisfy are (x, y, z) = (1, 2, 3).
we can use formula
we can compare
we get
a=x
b=2
now, we can plug that in formula
and we get
now, we can simplify it
...........Answer
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
