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Sedbober [7]
2 years ago
11

What is the perimeter of a square

Mathematics
2 answers:
german2 years ago
6 0
P=4a this is the answer
777dan777 [17]2 years ago
5 0

Answer:

4*sides

Step-by-step explanation:

4*sides is the Answer

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In Mexico people use pesos for money. There are about 12.8 pesos in
aleksklad [387]

Answer:

a peso worth is 5 cent

Step-by-step explanation:

i hope thag helps so 5 all tye ways to 100

5 0
2 years ago
PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
State in interval notation -1 -10 |2x- 10| greater than or equal to 19​
Elena-2011 [213]

no solution is the answer

7 0
3 years ago
Can you help plz I don’t get it
aleksklad [387]
The correct answer is A) x=3

What this picture demonstrates is 3 x’s on the left side and 9 ones on the right. So it says 3x=9. If you were to divide by 3, or multiply by 1/2, you’d have x=3.

Another way to think of it is by redrawing the picture. Each ‘x’ would get three “1’s” thus x=3
7 0
3 years ago
Help asap thank you
Alex777 [14]
1. The answer is $24
32x0.25= 8 32-8=24
2. The answer is $105
150x0.30=45 150-45=105
3. The answer is $52
80x0.35=28 80-28= 105
4. The answer is $59.25
14+25+40=79 79x0.25=19.75 79-19.75=59.25
8 0
3 years ago
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